Answer:
ΔU = 5.21 × 10^(10) J
Explanation:
We are given;
Mass of object; m = 1040 kg
To solve this, we will use the formula for potential energy which is;
U = -GMm/r
But we are told we want to move the object from the Earth's surface to an altitude four times the Earth's radius.
Thus;
ΔU = -GMm((1/r_f) - (1/r_i))
Where;
M is mass of earth = 5.98 × 10^(24) kg
r_f is final radius
r_i is initial radius
G is gravitational constant = 6.67 × 10^(-11) N.m²/kg²
Since, it's moving to altitude four times the Earth's radius, it means that;
r_i = R_e
r_f = R_e + 4R_e = 5R_e
Where R_e is radius of earth = 6371 × 10³ m
Thus;
ΔU = -6.67 × 10^(-11) × 5.98 × 10^(24)
× 1040((1/(5 × 6371 × 10³)) - (1/(6371 × 10³))
ΔU = 5.21 × 10^(10) J
Answer:
a) Left to right
b) 1.51 A
Explanation:
a)
The gravitational force on the rod due to its mass is in downward direction. hence to levitate the rod, the magnetic force on the rod must be in upward direction.
The magnetic field is inward to page and magnetic force must be upward. Using right hand rule, the current must be flowing from left to right.
Left to right
b)
L = length of the copper rod = 0.570 m
m = mass of the rod = 0.059 kg
B = magnitude of magnetic field in the region = 0.670 T
θ = Angle between the magnetic field and rod = 90
i = current flowing throw the rod = ?
The magnetic force on the rod balances the gravitational force on the rod. hence
Magnetic force = gravitational force
mg = i B L Sinθ
(0.059) (9.8) = i (0.670) (0.570) Sin90
i = 1.51 A
Answer:
3054.32618 rad/s²
-431.1989 rad/s²
29080
Explanation:
Converting angular speed to rad/s


The average acceleration while speeding up is 3054.32618 rad/s²
The number of turns in the 1.2 seconds

The number of rotations in the 1.2 seconds is 349.99
Number of rotations in the 45 seconds


Average angular acceleration while slowing down -431.1989 rad/s²

Number of rotations while slowing down is 2479.16718
Total number of rotations is 349.99+26250+2479.16718 = 29079.15718 = 29080
They cannot travel through D a vacuum. They need a solid, liquid or gas to travel<span />