An elements atomic number is 61. How many protons would an atom of this element have?_______

Compare and contrast carbon to its isotopes: what is different about them and what is the same?

Alex_Xolod [135]

Their atomic numbers are all the same, because they all have the same number of protons. But their atomic weights are different, because they have different numbers of neutrons.

6 0

4 years ago

Two object, one of mass m and the other of mass 2m, are dropped from the top of a building. if there is no air resistance, when

ra1l [238]

Answer:

They hit the ground at the same time

Explanation:

Mass doesn't matter in free fall. As long as they were released with the same velocity and the same height, they'll hit the ground at the same time

3 0

3 years ago

Michael is biking on a trail and is accelerating at a rate of 1.2 m/s/s for 15 seconds. He began this part of his ride with a ve

Serhud [2]

Answer:

Michael's final velocity is 19.62 m/s.

Explanation:

We can find the final velocity of Michael by using the following kinematic equation:

$v_{f} = v_{0} + at$ (1)

Where:

$v_{f}$ : is the final velocity =?

$v_{0}$ : is the initial velocity = 1.62 m/s

a: is the acceleration = 1.2 m/s²

t: is the time = 15 s

By entering the above values into equation (1) we have:

$v_{f} = 1.62 m/s + 1.2 m/s^{2}*15 s$

$v_{f} = 19.62 m/s$

Therefore, Michael's final velocity is 19.62 m/s.

I hope it helps you!

7 0

3 years ago

How long is a pendulum with a period of 1.0 S on the moon which has 1/6 of the earths gravity

k0ka [10]

For small deflections, T = 2*pi*sqrt(L / g) where T is period, L is length and g is gravity. Setting the equations to the same period, 2*pi*sqrt(3.85 / g) = 2*pi*(L / (1/6 * g)) The equation reduces to 3.85 m = 6 * L so L = 0.642 m chrsclrk · 7 years ago

7 0

3 years ago

Consider the cylindrical weir of diameter 3 m and length 6m. If the fluid on the left has a specific gravity of 0.8, find the ma

sladkih [1.3K]

This question is incomplete, the complete question is;

Consider the cylindrical weir of diameter 3m and length 6m. If the fluid on the left has a specific gravity of 1.6 and on the right has a specific gravity of 0.8, Find the magnitude and direction of the resultant force.

Answer:

- the magnitude of the resultant force is 557.32 kN

- the direction of resultant force is 48.29°

Explanation:

Given the data in the question and the diagram below,

First we work on the force on the left hand side.

Left Horizontal

$F_{LH$ = βgAr

here, h = 3/2 = 1.5 m, β = 1.6, g = 9.81 m/s², A = 3 m × 6 m = 18 m²

we substitute

$F_{LH$ = βgAh = ( 1.6 × 1000 ) × 9.81 × 18 × 1.5 = 423792 N

Left Vertical

$F_{LV$ = ( βgπh² / 2 ) × W

we substitute

$F_{LV$ = [ ( ( 1.6 × 1000 ) × 9.81 × π(1.5)² ) / 2 ] × 6 = 332845.458 N

Now we go to the right hand side

Right Horizontal

$F_{RH$ = βgAh

here, h' = 1.5/2 = 0.75 m, β = 0.8, g = 9.81 m/s², A = 1.5 m × 6 m = 9 m²

we substitute

$F_{RH$ = ( 0.8 × 1000 ) × 9.81 × 9 × 0.75 ) = 52974 N

Right Vertical

$F_{RV$ = ( βgπh² / 4 ) × W

we substitute

$F_{RV$ = [ ( ( 0.8 × 1000 ) × 9.81 × π(1.5)² ) / 4 ] × 6 = 83211.36 N

Hence

Fx = $F_{LH$ - $F_{RH$ = 52974 N - 423792 N = 370818 N

Fy = $F_{LV$ + $F_{RV$ = 332845.458 N + 83211.36 N = 416056.818 N

R = √( Fx² + Fy² ) = √[ (370818 N)² + (416056.818 N)² ] = 557323.3 N

R = 557.32 kN

Therefore, the magnitude of the resultant force is 557.32 kN

Direction of resultant force;

tanθ = Fy / Fx

we substitute

tanθ = 416056.818 N / 370818 N

tanθ = 1.121997

θ = tan⁻¹( 1.121997 )

θ = 48.29°

Therefore, the direction of resultant force is 48.29°

4 0

3 years ago

An elements atomic number is 61. How many protons would an atom of this element have?________ protons