The clumping of blood from mismatched blood types is a problem for a patient because

1 answer:

8 0

The ABO blood group classification is based on antigens on red blood cells and antibodies found in blood plasma.Blood type A has antigen A on the red blood cells and anti - B antibodies in the blood.Blood type B has antigen B on the red blood cells and anti - A antibodies in the blood.Blood type AB has both antigen A and B on the red blood cells but has no anti-A nor anti - B antibodies in the bloodBlood type O has no antigen on the red blood cells and has both anti -A and anti B antibodies in the blood.

You might be interested in

Sometimes a mutation is beneficial to an organism's fitness and can be passed on to offspring. What is likely to happen to the m

Cloud [144]

The mutation will become more common in offspring and increase the genetic variability in the gene pool.

5 0

3 years ago

A grad student has a culture of E. coli with a total volume of 1,800 mL, and OD reading at 550 nm of 1.7. He transfers 1 mL cult

Naily [24]

Answer:

Explanation:

We'll represent the dilution as the volume transferred/total volume in the tube after transfer. So for the first dilution, 1 ml of culture was added into 9ml of broth bringing the total volume to 10 ml i.e 1/10

For the second dilution, 0.1 mL was added to 0.9mL of broth bringing the total volume to 1mL i.e 0.1/1.0 (this is also the same as 1/10). In relation to the stock culture, this is represented as 1/100 (that is 1/10 (first dilution) * 1/10 (second dilution)

Giving that the same was done for dilution 3 and 4,

third dilution is represented as: 1/10 and the fourth as 1/10 as well

In relation to the stock, dilution 3 is 1/1000

dilution 4 is 1/10000

a. the dilution in the third tube is $\frac{1}{1000} = 10^{3$ or 1.0* $10^{3}$

b. the dilution spread onto the agar plate is the fourth dilution, that is, $\frac{1}{10000} = 10^{4}$ or $1.0*10^{4}$

c. Since the grad student got 386CFU/0.2mL (200 uL = 0.2mL),

the cells in 1mL is: 386/0.2 = 1930 = 1.93 * $10^{3}$

the cells in 1800mL is therefore 1930*1800 = 3,474,000 = 3.4*10 $10^{6}$

3 0

3 years ago

Why is it important that antibodies have a symmetrical quaternary structure? to enable binding to many different antigens to cre

Morgarella [4.7K]

It is important that antibodies have a symmetrical quaternary structure to create two identical binding sites for antigens. An antibody is a relatively large protein having a Y-shape. Plasma cells produce antibodies which are then used by the immune system to fight off pathogens (e.g. bacteria and virus). The antibody is able to recognize the antigen of the pathogen. It binds with it either to neutralize it directly or “tag” the microbe for future attack by other parts of the immune system.

3 0

3 years ago

As filtrate passes through the long loop of Henle, salt is removed and concentrated in the interstitial fluid of the kidney medu

storchak [24]

Answer:

Nephron is the functional unit of kidney. The kidney contains around 4 to 5 million of nephrons in their structure. These nephrons helps in the blood filtration.

The loop of Henley passes down the filtrate for the production of urine. The excess salt is removed from the loop and deposited in the medullary part of the kidney. This is important as the nephron can now become hyperosmotic medullary concentration and helps in the urine production.

7 0

3 years ago

HEY PLEASE HELP ' LOL ALMOST DONE

Nata [24]

This a tough one, and technically they all have to do with an authoritative body enforcing an environmental policy. But the most specific ones of them all would be the first sentence and the last two sentences.

4 0

3 years ago