Answer:
https://prnt.sc/ql75rv
This is a link to an image of the lewis structure.
Answer:
Oxygen and Carbon are in the non-metal section. Both are in 2nd period while Carbon is in group 4A and Oxygen is in group 6A.
Oxygen has more valence electrons than carbon. I wish I could give you a more accurate explanation why on paper, but all you need to do is count the electrons on the largest shell.
Here's the orbital notation of Carbon: 1s^2 2s^2 2px^1 py^1
Carbon's largest shell is 2. Count the electrons on shell 2, and you get 4 valence electrons.
Orbital notation of Oxygen: 1s^2 2s^2 2px^2 py^1 pz^1
Oxygen's largest shell is 2. So, like with carbon, count the electrons on the largest shell. You get 6.
There is a way easier way of interpreting this where you do not even have to write the orbital notation. I wish I can explain, but just know the periods and the group numbers.
My answer -
hydrogen acceptor any substance ( CYTOCHROME OXIDASE) that can become reduced by the addition of hydrogen, thus enabling the transfer and release of energy as in the ELECTRON TRANSPORT SYSTEM.
P.S
Have an AWESOME!!! day :)
There are 4 lone pairs of electrons present in the carbon dioxide molecule
Answer:
P₂ = 1.05 atm
Explanation:
Given data:
Initial temperature = 24.0 °C (24+273 = 297 K)
Initial pressure = 0.900 atm
Final pressure = ?
Final temperature = 75 °C (75 + 273 =348 K)
Volume = constant
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
0.900 atm / 297 K = P₂/348 K
P₂ = 0.900 atm × 348 K / 297 K
P₂ = 313.2 atm. K /297 K
P₂ = 1.05 atm
