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Eddi Din [679]
3 years ago
12

1. A gas at 24.0 Celsius and.900 atm fills a 0.95 Liter container.

Chemistry
1 answer:
dangina [55]3 years ago
4 0

Answer:

P₂ = 1.05 atm

Explanation:

Given data:

Initial temperature = 24.0 °C (24+273 = 297 K)

Initial pressure = 0.900 atm

Final pressure = ?

Final temperature = 75 °C (75 + 273 =348 K)

Volume = constant

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

0.900 atm / 297 K = P₂/348 K

P₂ = 0.900 atm × 348 K / 297 K

P₂ = 313.2 atm. K /297 K

P₂ = 1.05 atm

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At a certain temperature and pressure, one liter of CO2 gas weighs 1.95 g.
AysviL [449]

Answer:

1.332 g.

Explanation:

  • We can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • At the same T and P and constant V (1.0 L), different gases have the same no. of moles (n):

<em>∴ (n) of CO₂ = (n) of C₂H₆</em>

<em></em>

∵ n = mass/molar mass

<em>∴ (mass/molar mass) of CO₂ = (mass/molar mass) of C₂H₆</em>

mass of CO₂ = 1.95 g, molar mass of CO₂ = 44.01 g/mol.

mass of C₂H₆ = ??? g, molar mass of C₂H₆ = 30.07 g/mol.

<em>∴ mass of C₂H₆ = [(mass/molar mass) of CO₂]*(molar mass) of C₂H₆</em> = [(1.95 g / 44.01 g/mol)] * (30.07 g/mol) =<em> 1.332 g.</em>

<em></em>

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