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Eddi Din [679]
3 years ago
12

1. A gas at 24.0 Celsius and.900 atm fills a 0.95 Liter container.

Chemistry
1 answer:
dangina [55]3 years ago
4 0

Answer:

P₂ = 1.05 atm

Explanation:

Given data:

Initial temperature = 24.0 °C (24+273 = 297 K)

Initial pressure = 0.900 atm

Final pressure = ?

Final temperature = 75 °C (75 + 273 =348 K)

Volume = constant

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

0.900 atm / 297 K = P₂/348 K

P₂ = 0.900 atm × 348 K / 297 K

P₂ = 313.2 atm. K /297 K

P₂ = 1.05 atm

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Answer: 72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

Explanation:

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To calculate the number of moles, we use the equation:

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Putting in the values we get:

\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles

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3 years ago
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then let     1 L of solution contain  x  mol
      
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