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Eddi Din [679]
3 years ago
12

1. A gas at 24.0 Celsius and.900 atm fills a 0.95 Liter container.

Chemistry
1 answer:
dangina [55]3 years ago
4 0

Answer:

P₂ = 1.05 atm

Explanation:

Given data:

Initial temperature = 24.0 °C (24+273 = 297 K)

Initial pressure = 0.900 atm

Final pressure = ?

Final temperature = 75 °C (75 + 273 =348 K)

Volume = constant

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

0.900 atm / 297 K = P₂/348 K

P₂ = 0.900 atm × 348 K / 297 K

P₂ = 313.2 atm. K /297 K

P₂ = 1.05 atm

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nasty-shy [4]

There are 4 significant figures! Start counting after the first non-zero digit :)

Hope this helps.

3 0
3 years ago
Given the following equation, N2O(g) + NO2(g) → 3 NO(g) ΔG°rxn = -23.0 kJ
Lelechka [254]

Answer:

ΔG°rxn = -69.0 kJ

Explanation:

Let's consider the following thermochemical equation.

N₂O(g) + NO₂(g) → 3 NO(g) ΔG°rxn = -23.0 kJ

Since ΔG°rxn < 0, this reaction is exergonic, that is, 23.0 kJ of energy are released. The Gibbs free energy is an extensive property, meaning that it depends on the amount of matter. Then, if we multiply the amount of matter by 3 (by multiplying the stoichiometric coefficients by 3), the ΔG°rxn will also be tripled.

3 N₂O(g) + 3 NO₂(g) → 9 NO(g) ΔG°rxn = -69.0 kJ

8 0
3 years ago
G(1)=0 g(n) =g(n-1)+n g(2)=
Aliun [14]
G(2)=2

For this, you can plug in 2 everywhere you see an n. So the equation will read:
g(2)=g(2-1)+2 -> g(2)=g(1)+2. Since we are given g(1)=0, we can plug in 0 where we see g(1). The equation is now. g(2)=0+2. So, g(2)=2.
6 0
3 years ago
What can group numbers on the periodic table help you determine?
Ilia_Sergeevich [38]
Http://www.chem4kids.com/files/elem_pertable.html this should help.
4 0
3 years ago
Calculate the molar mass of iron(III) sulfide. Round your answer to the nearest 0.1 and include units to receive credit.
Igoryamba

Answer:

207.89g

Explanation:

The formula of the compound is:

        Fe₂S₃  

Find the molar mass of the compound;

  Atomic mass of Fe  = 55.845g/mol

                              S  = 32.065g/mol

Now;

  Molar mass of  Fe₂S₃   = 2 (55.845) + 3 (32.065)

                                         = 207.89g

8 0
3 years ago
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