Question

What is the energy of a radio wave photon with a frequency of 1.255 x 106 sec-1 ?

Answer 1

Answer:

The correct answer is option c.

Explanation:

$E=h\nu =\frac{h\times c}{\lambda}$

where,

E = energy of photon = ?

h = Planck's constant = $6.63\times 10^{-34}Js$

$\nu$ =- frequency of the wave

c = speed of light = $3\times 10^8m/s$

$\lambda$ = wavelength of the radio wave photon

Now put all the given values in the above formula, we get the energy of the photons.

$E=6.63\times 10^{-34}Js\times 1.255\times 10^6 s^{-1}$

$E=8.316\times 10^{-28}J$

Hence, the correct answer is option c.