3 years ago

Please help asap.........!!!!!!!!!

Mathematics

1 answer:

SOVA2 [1]3 years ago

8 0

Answer:

Step-by-step explanation:

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Hey u all what up u all

Arlecino [84]

Answer:

not too much, you?

Step-by-step explanation:

8 0

3 years ago

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587,504 rounded to the nearest ten thousand is

Kobotan [32]

590,000

87,504 it closer to 90,000 that 80,000 so 587,504 rounded to the nearest ten thousand is 59,000

8 0

3 years ago

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Which shows the correct substitution of the values a, b, and c from the equation 1 = –2x + 3x2 + 1 into the quadratic formula? Q

Tanzania [10]

First of all, you have to manipulate the equation into the standard

$ax^2+bx+c=0$

form. You can simplify the 1's on both sides and you have

$3x^2-2x=0$

This means that your coefficients are

$a=3,\quad b=-2,\quad c=0$

And since the solving formula is

$x_{1,2}=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plugging your values yields

$x_{1,2}=\dfrac{-(-2)\pm\sqrt{(-2)^2-4\cdot 3\cdot 0}}{2\cdot 3}$

5 0

3 years ago

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Need help with part b please ??

Scorpion4ik [409]

Answer:

The function is never decreasing.

Step-by-step explanation:

The function is never decreasing because as x increases, y also increases.

3 0

3 years ago

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<img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5E2_1%20%7Bx%5E%7B2%7D-8x%2B8%20%7D%20%5C%2C%20dx" id="TexFormula1" title="\in

12345 [234]

Answer:

${ \underline{ \sf{\int\limits^2_1 {x^{2}-8x+8 } \, dx} \: = \: - 1}}$

Step-by-step explanation:

${ \tt{\int\limits^2_1 {x^{2}-8x+8 } \, dx}} \\ \\ = { \tt{[ \frac{ {x}^{3} }{3} - 4 {x}^{2} + 8x ] {}^{2} _{1}}}$

Substitute x with the limits:

$= { \tt{( \frac{ {2}^{3} }{3} - 4( {2)}^{2} + 8(2)) - ( \frac{ {1}^{3} }{3} - 4( {1)}^{2} + 8(1)) }} \\ = { \tt{( \frac{8}{3} - \frac{11}{3} )}} \\ \\ = { \tt{ - 1}}$

4 0

3 years ago