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natali 33 [55]
4 years ago
11

Two trucks started toward each other at the same time from towns 500 km apart. One truck traveled at a rate of 65 km per hour wh

ile the other traveled at 60 km per hour. After how many hours did they meet? 1 x represents the number of hours, which of the following equations could be used to solve the problem? 65x60x500 65x60x500 65x60x ​
Mathematics
1 answer:
Alex73 [517]4 years ago
3 0

Answer:

65x + 60x = 500

Step-by-step explanation:

yep

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Find the equation of a line that passes through these two points
Sati [7]

Answer:

y = -2x + 2

Step-by-step explanation:

The equation of a line is y = mx + b.

First we want to find m, the slope. We can used the coordinates to do so: m = \frac{6-(-4)}{-2-3}\\m = \frac{10}{-5}\\m = -2

Now we know that the equation is y = -2x + b. We can plug in the coordinate (3, -4) to find b.

y = -2x + b\\-4 = -2(3) + b\\-4 = -6 + b\\b = 2

So the equation is y = -2x + 2.

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3 years ago
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Lady_Fox [76]

Answer:

<h2> I am not so good at drawing .</h2><h3>BE = 3.6</h3>

6 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST!
svetoff [14.1K]

Answer:

x=4.5 or 9/2

Step-by-step explanation:

\frac{6}{3}=\frac{9}{x}

Then, cross multiply

6×X=6x

9×3=27

6x=27

x=4.5

8 0
3 years ago
Simplify the expression shown below: (a^3b^12c^2)^2(a^5c^2)^3(b^5c^4)^0
NemiM [27]
= a^21b^24c^10 
use the product rules for each set of () then multiply them together. when multiplying variables with exponents you just add them together like for a^3 * a^5 = a^8.     (a^3 b^12 c^2)^2 = (a^6 b^24 c^4)
4 0
3 years ago
a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
12345 [234]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

6 0
3 years ago
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