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2 years ago

PLS ANSWER ASAP NEED HELP

Mathematics

1 answer:

ruslelena [56]2 years ago

7 0

Answer:

0.5

Step-by-step explanation:

. ..........ur welcome...........

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Suppose you work in a grocery store 4 hours on Friday and 5 hours on Saturday. You earn $6.25 an hour.

Shalnov [3]

Answer:

If the quetion is how much money I earned on both days it would be 56.25

Step-by-step explanation:

4hours times 6.25 an hour = 25 now we do 5hours times 6.25 an hour = 31.25 so add them to get 56.25

5 0

2 years ago

I need help on this problem!!

Svetllana [295]

$3.98*10^{6}(people)*\frac{1 mi^{2}}{1000 people} = 3.98*10^{6}* \frac{1 mi^{2}}{10^{3}} = 3.98*10^{6-3} mi^{2}=

=3.98*10^{3} mi^{2}$

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2 years ago

A certain vibrating system satisfies the equation . Find the value of the damping coefficient for which the quasi period of the

Likurg_2 [28]

Answer:

Hence the value of damping coefficient = 1.49071.

Step-by-step explanation:

7 0

2 years ago

What is StartFraction one-half EndFraction x is less than or equal to 18.x ≤ 18

Eduardwww [97]

Answer:

$x\leq 36$

The solution for $x$ is all real numbers less that or equal to 36.

Step-by-step explanation:

Given expression:

$\frac{1}{2}x\leq18$

To find the solution for $x$

Solution:

In order to solve for $x$ , we will make sure to isolate the unknown variable $x$ on left side alone by doing math operations on both sides of the inequality.

We have:

$\frac{1}{2}x\leq18$

Multiplying both sides by 2.

$2.\frac{1}{2}x\leq18\times 2$

The 2 on left side will cancel each other leaving $x$ alone.

Thus, we have:

$x\leq 36$

Thus, solution for $x$ is all real numbers less that or equal to 36.

7 0

2 years ago

Read 2 more answers

ind the value of the test statistic z using z equals StartFraction ModifyingAbove p with caret minus p Over StartRoot StartFract

Sergeeva-Olga [200]

Answer:

$z=\frac{0.262 -0.25}{\sqrt{\frac{0.25(1-0.25)}{530}}}=0.638$

Step-by-step explanation:

Data given and notation

n=530 represent the random sample taken

X=139 represent the yellow pods in the random sample

$\hat p=\frac{139}{530}=0.262$ estimated proportion of yellow pods

$p_o=0.25$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.25 or 25%:

Null hypothesis: $p=0.25$

Alternative hypothesis: $p \neq 0.25$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.262 -0.25}{\sqrt{\frac{0.25(1-0.25)}{530}}}=0.638$

6 0

2 years ago