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Makovka662 [10]
3 years ago
7

Consider the diagram

Mathematics
1 answer:
Dafna11 [192]3 years ago
7 0
Idk hahahahcthnkkyggbjjgyuu
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A. 782341/491675 = 1.5911750648294096710225250419484, or a growth rate of 59% over 10 years. So:(1+k)^10 = 1.5911750648294096710225250419484ln (1+k)^10 = ln 1.591175064829409671022525041948410 ln(1+k) = ln 1.5911750648294096710225250419484ln(1+k) = ln 1.5911750648294096710225250419484/10 = 0.04644727777645335179835425806392e^0.04644727777645335179835425806392 = 1+kk = 1.0475428488243655419718940009655, or 4.75428488243655419718940009655% growth rate per year.

B. Population year t = 491675 x (1.0475)^(t-2000)

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What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a
Anarel [89]

Answer:

Average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: f(x)= x^2-x-1

The formula used to find average rate of change is:

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}

We have, a = -1 and b = 1

Finding f(b) when b=1

f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1

Now, finding f(a), when a= -1

f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1

Now, putting values and finding average rate of change

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1

So, average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

4 0
3 years ago
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