What is the Scale Factor going from the larger figure to the smaller figure?

Pls help I need this right now!!!

Anettt [7]

D: 18%

Hope it helps

4 0

3 years ago

Answer number 7 and explain your answer

oksano4ka [1.4K]

Answer:

82 degrees.

Step-by-step explanation:

The lines AB, HG, IJ, and DC are parallel lines and the line DB is the transversal that is intersecting this group of parallel lines. It is given that the angle formed by the intersection of HG and DB is 98 degrees. Since the line is straight, the supplementary angle can be calculated by subtracting 98 degrees from 180 degrees, which is 82 degrees. Alternate angles are the angles that are formed by the intersection of the group of parallel lines and the transversal on the opposite sides of the transversal. The angles are corresponding angles if they are present on the same side of the transversal. Due to the property of corresponding angles, the angles formed by the intersection of IJ and DB are also 98 degrees and 82 degrees respectively. By the property of the alternate angles, the angle BDC is also 82 degrees. Therefore, 82 degrees is the correct answer!!!

7 0

3 years ago

The number 39 is decreased to 38. What is the percentage by which the number was decreased, to the nearest tenth of a percent?

djverab [1.8K]

39-38=1
1÷39=0.025
0.025x100= 3% decrease

3 0

4 years ago

Please help! Will give brainliest, thanks and more points.<br><br> Look at the picture.

scZoUnD [109]

1296 because the volume of a pyramid is 1/3 lwh so you would multiply 18*18*12 and then divide that sum by three to get the answer.

6 0

3 years ago

A car ride is drawn on a coordinate plane so that the first card is located at the point by (5,10) what are the coordinates of t

Rudiy27

Answer:

There are two possible solutions:

Clockwise rotation

$P'(x,y) = (-10,5)$

Counterclockwise rotation

$P'(x,y) = (10, -5)$

Step-by-step explanation:

There are two possible answers: (i) Clockwise rotation, (ii) Counterclockwise rotation. Vectorially speaking, rotation of point of rotation of a point about another point of reference is defined by:

$P'(x,y) = O(x,y) + r_{OP}\cdot (\cos (\theta_{OP}\pm \theta'),\sin (\theta_{OP}\pm \theta'))$ (1)

Where:

$O(x,y)$ - Point of reference.

$r_{OP}$ - Length of the segment OP.

$\theta_{OP}$ - Direction of segment OP, measured in sexagesimal degrees.

$\theta '$ - Angle of rotation, measured in sexagesimal degrees.

Please notice that clockiwise rotation occurs when $\theta = \theta_{OP}-\theta'$ and counterclockwise rotation when $\theta = \theta_{OP}+\theta'$ . In addition, we define length and direction of the segment below:

$r_{OP} = \sqrt{(x_{P}-x_{O})^{2}+(y_{P}-y_{O})^{2}}$ (1)

$\theta_{OP} = \tan^{-1} \frac{y_{P}-y_{O}}{x_{P}-x_{O}}$

If we know that $x_{O} = y_{O} = 0$ , $x_{P} = 5$ , $y_{P} = 10$ and $\theta' = 270^{\circ}$ , then the coordinates of the first car after rotation is: