The endpoints of a line segment graphed on the coordinate system are (−7, 3) and (2, 5). What is the range of the graph?

Below is the five Number summary for a 136 hikers who recently completed the John muir trail JMT the variable is the amount of t

Helga [31]

Answer:

$IQR = Q_3 -Q_1 = 28-18 = 10$

Now we can find the limits in order to determine outliers like this:

$Left = Q_1 -1.5 IQR = 18 -1.5*10=3$

$Right = Q_1 +1.5 IQR = 18 +1.5*10=33$

So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier

b. 3

Step-by-step explanation:

For this case we have the following summary:

$Minimum = 9$ represent the minimum value

$Q_1 = 18$ represent the first quartile

$Median =Q_2= 21$ represent the median

$Q_3 = 28$ represent the third quartil

$Maximum=56$ represent the maximum

If we use the 1.5 IQR we need to find first the interquartile range defined as:

$IQR = Q_3 -Q_1 = 28-18 = 10$

Now we can find the limits in order to determine outliers like this:

$Left = Q_1 -1.5 IQR = 18 -1.5*10=3$

$Right = Q_1 +1.5 IQR = 18 +1.5*10=33$

So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier

b. 3

7 0

2 years ago

What is the perimeter (in feet and inches) of a rectangle that has a length of 12'7" and a height of 11'3"?

elena-14-01-66 [18.8K]

Answer:

p=2l+2w

=2*12'7"+2*11'3"

7 0

2 years ago

Five friends split a $65.20 bill at a restaurant . They also each left $2.75 for the tip. How much money did each person pay in

kvv77 [185]

You start by doing 65.20 (the bill) divided by 5 (the amount of people paying)
65.20 / 5 = 13.04

Then you add 13.04 (how much each person paid towards the bill) and 2.75 (the amount of money each person left as a tip)
13.04 + 2.75 = 15.79

Each person paid $15.79

4 0

2 years ago

Read 2 more answers

Which of the following is not a possible number of solutions when solving a system of equations containing a quadratic and a lin

Kobotan [32]

Answer:

3

Step-by-step explanation:

We have a system with two equations, one equation is a quadratic function and the other equation is a linear function.

To solve this system we have to clear "y" in both equations, and then equal both equations, then we will have a quadratic function and equal it to zero:

$ax^2+bx+c=0, a\neq 0$

Then to resolve a quadratic equation we apply Bhaskara's formula:

$x_{1}=\frac{-b+\sqrt{b^2-4ac} }{2a}$

$x_{2}=\frac{-b-\sqrt{b^2-4ac} }{2a}$

It usually has two solutions.

But it could happen that $\sqrt{b^2-4ac}$ then the equation doesn't have real solutions.

Or it could happen that there's only one solution, this happen when the linear equation touches the quadratic equation in one point.

And it's not possible to have more than 2 solutions. Then the answer ir 3.

For example:

In the three graphs the pink one is a quadratic function and the green one is a linear function.

In the first graph we can see that the linear function intersects the quadratic function in two points, then there are two solutions.

In the second graph we can see that the linear function intersects the quadratic function in only one point, then there is one solutions.

In the third graph we can see that the linear function doesn't intersect the quadratic function, then there aren't real solutions.

7 0

3 years ago

Which expression is equivalent to StartFraction 4 f squared Over 3 EndFraction divided by StartFraction 1 Over 4 f EndFraction?

Rama09 [41]

Hdhdindndhshdnidneididndkjfkd

3 0

2 years ago

Read 2 more answers