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hram777 [196]
3 years ago
7

The data below represents the number of desks on each floor of Texter Corporate.

Mathematics
1 answer:
xxMikexx [17]3 years ago
4 0

Answer:

Box-plot = {54, 65, 69, 73, 76}

Step-by-step explanation:

The data provided for the number of desks on each floor of Texter Corporate is as follows:

S = {54, 60, 65, 66, 67, 69, 70, 72, 73, 75, 76}

There are a total of <em>n</em> = 11 floors.  

A boxplot, also known as a box and whisker plot is a method to demonstrate the distribution of a data-set based on the following 5 number summary,

  • Minimum (shown at the bottom of the chart)
  • First Quartile (shown by the bottom line of the box)
  • Median (or the second quartile) (shown as a line in the center of the box)
  • Third Quartile (shown by the top line of the box)
  • Maximum (shown at the top of the chart).

Arrange the data in ascending order as follows:

S': = {54 , 60 , 65 , 66 , 67 , 69 , 70 , 72 , 73 , 75 , 76}

The minimum value is:

Minimum = 54

The maximum value is:

Maximum = 76

As there are odd number of values the median is the middle value.

Median = 6th value = 69

The first quartile is the median of the first half of the data.

S'₁ = {54 , 60 , 65 , 66 , 67}

First quartile = 3rd value = 65

The third quartile is the median of the second half of the data.

S'₂ = {70 , 72 , 73 , 75 , 76}

Third quartile = 3rd value = 73

Thus, summarized data for the box plot is:

Box-plot = {54, 65, 69, 73, 76}

The box plot is attached below.

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<h3><u>Answer the following questions :-</u></h3>

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Check the Raja's rate list and solve the following questions.

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \small\boxed{\begin{array}{c|c} \bf{Kind  \: of\:junk} & \bf{Price  \: of \:  1  \: kg } \\ \dfrac{\qquad\qquad\qquad}{ \sf News \:  Paper} &\dfrac{\qquad \qquad\qquad}{ \sf Rs.5} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Iron} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.10} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Brass} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.50} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Plastic} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.8}&\end{array}} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

<h2><u>Solutions :-</u></h2>

1. How much money will you pay to Raju for 20 kg of newspapers?

\quad{\longrightarrow{\sf{Cost \: of \:  1  \: kg  \: newspaper = Rs.5}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  20  \: kg  \: newspaper = Rs.20 \times 5}}}

\quad{\longrightarrow{\sf{Cost \: of \:  20  \: kg  \: newspaper = Rs.100}}}

\quad{\longrightarrow{\underline{\boxed{\sf{\purple{Cost  \: of \:  20  \: kg  \: newspaper = Rs.100}}}}}}

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2. What is the cost of 5 kg Iron?

\quad{\longrightarrow{\sf{Cost\: of \:  1  \: kg  \: iron = Rs.10}}}

\quad{\longrightarrow{\sf{Cost\: of \:  5  \: kg  \: iron = Rs.10 \times 5}}}

\quad{\longrightarrow{\sf{Cost \: of \:  5  \: kg  \: iron = Rs.50}}}

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\quad{\longrightarrow{\sf{Cost  \: of \:  9  \: kg  \: plastic = Rs.72}}}

\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost\: of \:  9  \: kg  \: plastic = Rs.72}}}}}

<u>∴ The cost of 9 kg plastic is Rs.72. </u>

\rule{200}{1.5}

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\quad{\longrightarrow{\sf{Cost\: of \:  7  \: kg  \: brass = Rs.50 \times 7}}}

\quad{\longrightarrow{\sf{Cost  \: of \:  7  \: kg  \: brass = Rs.350}}}

\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost  \: of \:  5  \: kg  \: brass = Rs.350}}}}}

<u>∴ The cost of 7kg brass is Rs.350.</u>

\underline{\rule{200pt}{2pt}}

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