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Romashka-Z-Leto [24]
2 years ago
9

The minimum and maximum temperature on a cold day can be modeled by the equation 2[x-6]+14=38 What are the min and max temperatu

res for this day?
Mathematics
2 answers:
SashulF [63]2 years ago
6 0
Here are the steps to calculating the given equation:

Distribute 2 to x and 6: 2x-12+14=38
Group like terms: 2x+(-12+14)=38
Combine like terms: 2x+2=38
Subtract number on 'x' side: 2x+2-2=38-2
Simplify: 2x=36
Divide: 2x/2=36/2
Simplify: x=18
Label with correct terms: 
I cannot do this because you did not provide sufficient information, I would need to know what the difference between the two, or if 'x' stood for one particular temperature. Hope that helped enough with what you provided.
Nimfa-mama [501]2 years ago
3 0

assuming the brackets are absolute values, the max would be 18 and the min you be -6

there are always two solutions when it comes to absolute value if it begins with something higher than zero

x = 18

x = -6

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Answer:

<h2>0</h2>

Step-by-step explanation:

30x = 30 - 30

=  > 30x = 0

=  > x =  \frac{0}{30}

=  > x = 0

5 0
2 years ago
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Does the equation y=2x+1 represent an equation
soldi70 [24.7K]
This represents a function with a slope of 2 and y-intercept of 1
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One survey estimates that,on average, the retail value of a mid sized car decreases by8% annually.if the retail value of a car i
Scrat [10]
Percentage by which the average value of mid sized car decreases each year = 8%
Retail value of a car today = v dollars
Amount of decrease in the value of the car after 1 year = (8/100) * v
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Then
The equation that represents the value of the car after 1 year = v - (2v/25) dollars
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5 0
3 years ago
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2296.0 m= ____________ km in metric conversions
Andreyy89

Answer:

2.296 km

Step-by-step explanation:

The "meters to kilometers" conversion factor is:

 1 km

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3 0
3 years ago
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Which statements are true?<br>(look at picture)​
Makovka662 [10]

Answer:

D is true, E is true, F is true

Step-by-step explanation:

Hello,

n is an odd number it means that n = 2a+1 where a is integer

A

n^2-1=(2a+1)^2-1=4a^2+4a+1-1=4a(a+1)

this is <u>not</u> an odd number

B

n(n-1)=(2a+1)2a

this is <u>not</u> an odd number

C

(n-1)^2=(2a+1-1)^2=4a^2

this is <u>not</u> an odd number

D

n^2+2=(2a+1)^2+2=4a^2+4a+1+2=4a^2+4a+3= 2(2a^2+2a+1)+1

so this is an odd number

E

n(n-2)=(2a+1)(2a-1)=4a^2-1=4a^2-2+1=2(2a^2-1)+1

so this is an odd number

F

(n-2)^2=(2a+1-2)^2=(2a-1)^2=4a^2-4a+1 = 2(2a^2-2a)+1

this is an odd number

hope this helps

7 0
3 years ago
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