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Sliva [168]
3 years ago
14

A gas occupies 3.5 L at 2.5 mm Hg pressure what is the volume at 10 mm Hg at the same tempature

Chemistry
1 answer:
mrs_skeptik [129]3 years ago
7 0
(2.5)(3.5)=10V²



The answer is 0.875 repeating liters.
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How much heat is required to decompose 25.5 grams of NaHCO3? 2NaHCO3(s) + 129 kJ 2Na2CO3(s) + H2O(g) + CO2(g)
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The chemical equation is missbalaced.


The right balanced chemical equation is:


<span>2NaHCO3(s) + 129 kJ ---> Na2CO3(s) + H2O(g) + CO2(g)



Then, now you know that 2 moles of NaHCO3 requires 129 kJ heat, and you just need to convert 25.5 grams of NaHCO3 into number of moles to calculare the amount of heat needed.


A) Number of moles in 25.5 g of NaHCO3, n:

n = grams / molar mass


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2mol / 129 kJ = 0.304 mol / x


=> x = 0.304 mol * 129 kJ / 2 mol =  19.608 kJ


Answer: 19.6 kJ
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