Answer:
Answers are in the explanation
Explanation:
Equlibrium of HF in H₂O is:
HF + H₂O ⇄ F⁻ + H₃O⁺
Now, the KOH reacts with HF, thus:
KOH + HF → F⁻ + H₂O
<em>That means after reaction, concentration of HF decrease increasing F⁻ concentration.</em>
Now, seeing the equilibrium, as moles of HF decrease and F⁻ moles increase, the equilibrium will shift to the left decreasing H₃O⁺ concentration.
For the statements:
A. The number of moles of HF will increase. <em>FALSE</em>. HF react with KOH, thus, moles of HF decrease
B. The number of moles of F- will decrease. <em>FALSE</em>. The reaction produce F⁻ increasing its moles.
C. The equilibrium concentration of H₃O⁺ will increase. <em>FALSE. </em>The equilibrium shift to the left decreasing concentration of H₃O⁺
D. The pH will decrease. <em>FALSE</em>. As the H₃O⁺ concentration decrease, pH will increase
E. The ratio of [HF] / [F-] will remain the same. <em>FALSE</em>. Because moles of HF are decreasing whereas F- moles are increasing changing, thus, ratio.
