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3 years ago

Writing Prompt/Open-Ended Question

Chemistry

1 answer:

tino4ka555 [31]3 years ago

8 0

Answer:

If you are given a chemical equation and specific amounts for each reactant in grams, you have to follow these steps, in order, to determine how much product can possilby be made:

1. Convert each reactant into moles of the product.

2. Determine which reactant is the limiting reactant.

3. Convert the moles of product, from the limiting reactant, to grams.

Explanation:

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In the Inca civilization what was the quipo used for?

Rudik [331]

It involved knots in strings called quipu. The quipu was not a calculator, rather it was a storage device. Remember that the Incas had no written records and so the quipu played a major role in the administration of the Inca empire since it allowed numerical information to be kept.

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3 years ago

The largest ruby isnthe world is 10.9 cm long, 9.1 cm wide and 5.8 cm thick, giving

Maslowich

You have to use density=mass/volume formula:

$3.97= \frac{x}{575}$

Solve for x and you get 2282.75 grams

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3 years ago

A student dissolves 3.9g of aniline (C6H5NH2) in 200.mL of a solvent with a density of 1.05 g/mL . The student notices that the

Tresset [83]

Answer:

a. Molarity= $M =2.1x10^{-1}M$

b. Molality= $m=2.0x10^{-1}m$

Explanation:

Hello,

In this case, given the information about the aniline, whose molar mass is 93g/mol, one could assume the volume of the solution is just 200 mL (0.200 L) as no volume change is observed when mixing, therefore, the molarity results:

$M=\frac{n_{solute}}{V_{solution}} =\frac{3.9g*\frac{1mol}{93g} }{0.2L} =2.1x10^{-1}M$

Moreover, the molality:

$m=\frac{n_{solute}}{m_{solvent}} =\frac{3.9g*\frac{1mol}{93g} }{0.2L*\frac{1.05kg}{1L} } =2.0x10^{-1}m$

Best regards.

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3 years ago

The maximum efficiency possible in an energy conversion process that is not limited by the second law of thermodynamics

Anna [14]

Answer:

100 %

Explanation:

The maximun efficiency possible (whem not limited by the second law of thermodynamics) happens when all the energy used is transformed into the type of energy we required with no other transformations.

For example, in an engine we want that all the energy we supply is being converted to work. That's the ideal case, but in reality always some of that energy is lost in the form of heat.

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3 years ago

C(S)+O2(g)-->CO2(g)

soldi70 [24.7K]

<u>Answer:</u> The correct answer is 1.18 g.

<u>Explanation:</u>

We are given a chemical equation:

$C(S)+O2(g)\rightarrow CO_2(g)$