Answer:
20. 
22. 
24. 
Step-by-step explanation:
20. 
The GCF is x, so you group it out of the equation first.
Then, you find 2 numbers that will equal to 2 when you add them and will equal to -48 when you multiply them.
The two numbers would be -6 and 8. You then differentiate the squares.
22. 
The GCF is 2, so you must group it out.
Find the two numbers that will equal to 5 when you add them and will equal to 4 when you multiply them.
The two numbers would be 1 and 4. Finally, differentiate the squares.
24. 
The GCF is 5m, so you must group it out.
Find the two numbers that will equal to 6 when you add them and will equal to -7 when you multiply them.
The two numbers would be -1 and 7. Finally, differentiate the squares.
Answer:
πr²= 12.56
r²=12.56/3.14 = 4
r= 2
therefore , diameter = 2r = 2×2= 4 mm
Answer:
10
Step-by-step explanation:
You have to go up 10 places to get from the first point to the second
You also have to go 1 place to the right
Since the slope is Y/X, the slope of this line is 10/1
Answer:
x³ - (√2)x² + 49x - 49√2
Step-by-step explanation:
If one root is -7i, another root must be 7i. You can't just have one root with i. The other roos is √2, so there are 3 roots.
x = -7i is one root,
(x + 7i) = 0 is the factor
x = 7i is one root
(x - 7i) = 0 is the factor
x = √2 is one root
(x - √2) = 0 is the factor
So the factors are...
(x + 7i)(x - 7i)(x - √2) = 0
Multiply these out to find the polynomial...
(x + 7i)(x - 7i) = x² + 7i - 7i - 49i²
Which simplifies to
x² - 49i² since i² = -1 , we have
x² - 49(-1)
x² + 49
Now we have...
(x² + 49)(x - √2) = 0
Now foil this out...
x²(x) - x²(-√2) + 49(x) + 49(-√2) = 0
x³ + (√2)x² + 49x - 49√2
Answer:
DNE
Step-by-step explanation:
As you can see in the picture I attached to this, that as the limit goes to zero from the negative side, it approaches -∞ and from the positive side, it approaches ∞ . hence, the limit doesn't exist.
To show this algebraically, you have to imagine how a number divided by zero looks like, Just know the graph of 1/x and see how the limit to zero doesnot exist. I hope this helps!
