Answer:
(2,1)
Step-by-step explanation:
We can see that the given triangle.
The coordinates of A are (-1,5) .
The coordinates of B are (-1,-3).
The coordinates of C are (5,-3).
Distance formula: ![\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
AB=
units
BC=
units
AC=
units
Pythagoras theorem:![(Hypotenuse)^2=(Base)^2+(Perpendicular\;side)^2}](https://tex.z-dn.net/?f=%28Hypotenuse%29%5E2%3D%28Base%29%5E2%2B%28Perpendicular%5C%3Bside%29%5E2%7D)
![AB^2+BC^2=8^2+6^2=100](https://tex.z-dn.net/?f=AB%5E2%2BBC%5E2%3D8%5E2%2B6%5E2%3D100)
![AC^2=(10)^2=100](https://tex.z-dn.net/?f=AC%5E2%3D%2810%29%5E2%3D100)
Therefore, ![AC^2=AB^2+BC^2](https://tex.z-dn.net/?f=AC%5E2%3DAB%5E2%2BBC%5E2)
When a triangle satisfied the Pythagoras theorem then, the triangle is right triangle.
Hence, the given triangle is a right triangle.
We know that circum-center of right triangle is the mid point of hypotenuse.
Mid-point formula:![x=\frac{x_1+x_2}{2},y=\frac{y_1+y_2}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%2Cy%3D%5Cfrac%7By_1%2By_2%7D%7B2%7D)
Using this formula then, we get
Mid-point of hypotenuse AC is given by
![x=\frac{-1+5}{2}=2,y=\frac{5-3}{2}=1](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-1%2B5%7D%7B2%7D%3D2%2Cy%3D%5Cfrac%7B5-3%7D%7B2%7D%3D1)
Hence, the circum-center of triangle is (2,1).
the answer is c because 0 to 6 is plus 6, then 6 to 16 is plus ten. ten and six are not the same number, therefore it is nonlinear.
2(w+6)
2•w = 2w
2•6 = 12
2w+12 ? I hope this helped ♀️
Answer:
Present age of john= 24 years
Let Shane's age= x years
Two years ago
John's age = 24-2= 22 years
Shane's age = (x-2) years
Writing in terms of equation,to the above statements
⇒22= 2(x-2)
⇒22= 2 x- 4
⇒22+4 = 2 x
⇒ 2 x= 26
⇒ x= 26÷2
⇒ x =13
Present age of son = 13 years