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erica [24]
4 years ago
12

Identify each of the highlighted materials as an element, a compound, or a mixture, and explain your reasoning.

Chemistry
2 answers:
gulaghasi [49]4 years ago
7 0

Answer 1) Butane : It is a compound which is made up by combination of elements of carbon and hydrogen together. It contains four carbon atoms which has ten atoms of hydrogen. The bonds between carbon and hydrogen are formed by covalently sharing of electrons. Therefore, butane is a compound.

Answer 2) Benzene : It is also a compound. Benzene contains six molecules of carbon and six molecules of hydrogen. They are covalently bonded with hydrogen atoms around the carbon atoms. It is termed as compound because it cannot be separated chemically.

Answer 3) Gasoline : This is an example of mixture. Gasoline usually contains mixture of many hydrocarbons in the compound state. It consists of mainly hydrocarbons which are between 4 to 12 carbon atoms per molecule (C4 - C12). It is majorly has the mixture of paraffins (which are alkanes), cycloalkanes (which are naphthenes), and olefins (which are alkenes). So, it will be correct to assign the term mixture to gasoline.

Answer 4) Kerosene - It is a mixture. Kerosene is made up of mixture of hydrocarbons. The chemical composition mainly depends on its source, but it usually consists of about ten different hydrocarbons, where each contains ten to sixteen carbon atoms per molecule. Therefore, assigning kerosene as a mixture is correct.

Answer 5) O_{2} - It is an element. The molecular formula of oxygen is O_{2}. Which states that when found in diatomic state the oxygen is stable and can exist freely in nature. The elemental form of oxygen is in the diatomic form. Therefore, oxygen ( O_{2}) is an element.

shtirl [24]4 years ago
6 0
We identify these substances as follows:

<span>Butane - compound
It has a chemical formula C4H10. It consists of 14 atoms - 4 atoms of carbon and 10 atoms of hydrogen. These are being bonded to form a molecule which makes it a compound.

Benzene - compound
It has a formula C6H6. It has 6 atoms of carbon and 6 atoms of hydrogen that are bonded together to form a molecule. Thus, it is a compound.

gasoline - mixture
It consists of different substances or compounds which makes it a mixture of those substances.

kerosene - mixture
It consists of different substances especially hydrocarbons.

O2 - compound
It consists of 2 oxygen atoms which are covalently bonded forming a molecule thus it is a compound</span>
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Suppose you made 40 atoms of Highlinium and it has a
Karo-lina-s [1.5K]

Answer:

After 6sec 5 atoms will be left.

Explanation:

Given data:

Total atoms of Highlinium = 40

Half life = 2 sec

Atoms left after 6sec = ?

Solution:

First of all we will calculate the number of half lives passes during 6sec.

Number of half lives = Time elapsed/ half life

Number of half lives = 6 sec / 2sec

Number of half lives = 3

Now we will calculate the number of atoms left

At time zero = 40 atoms

At 1st half life = 40 atoms/2 = 20 atoms

At 2nd half life = 20 atoms/2 = 10 atoms

At 3rd half life = 10 atoms / 2 = 5 atoms

Thus, after 6sec 5 atoms will be left.

6 0
3 years ago
What is the primary cause of diffusion? some substances can dissolve in solvents heat added to a substance random internal motio
Nina [5.8K]

Answer:

random internal motion of atoms and molecule

Explanation:

The primary cause of diffusion is the random internal motion of atoms and molecules.

Randomness of atoms and molecules results in diffusion.

  • Diffusion is the movement of particles from a region of high concentration to that of lower concentration.
  • Substances often tend to spread out over the concentration gradient.
  • Therefore, they have this propensity to be randomized.
3 0
3 years ago
Nitrogen dioxide is used industrially to produce nitric acid, but it contributes to acid rain and photochemical smog. What volum
Strike441 [17]

Answer:

35.41 L

Explanation:

Given, Volume of Copper = 4.84 cm³

Density = 8.95 g/cm³

Considering the expression for density as:

Density=\frac {Mass}{Volume}

So,

So, Mass= Density  Volume = 8.95 g/cm³  4.84 cm³ = 43.318 g

Mass of copper = 43.318 g

Molar mass of copper = 63.546 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{43.318\ g}{63.546\ g/mol}

Moles of copper = 0.6817 moles

Given, Volume of nitric acid solution = 227 mL = 227 cm³

Density = 1.42 g/cm³

Considering the expression for density as:

Density=\frac {Mass}{Volume}

So,

So, Mass= Density  Volume = 1.42 g/cm³  227 cm³ = 322.34 g

Also, Nitric acid is 68.0 % by mass. So,  

Mass of nitric acid = \frac {68}{100}\times 322.34\ g = 219.1912 g

Molar mass of nitric acid = 63.01 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{219.1912\ g}{63.01\ g/mol}

Moles of nitric acid = 3.4786 moles

According to the reaction,  

Cu_{(s)}+4HNO_3_{(aq)}\rightarrow Cu(NO_3)_2_{(aq)} + 2NO_2_{(g)} + 2H_2O_{(l)}

1 mole of copper react with 4 moles of nitric acid

Thus,  

0.6817 moles of copper react with 4*0.6817 moles of nitric acid

Moles of nitric acid required = 2.7268 moles

Available moles of nitric acid = 3.4786 moles

Limiting reagent is the one which is present in small amount. Thus, nitric acid is present in large amount, copper is the limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of copper on reaction forms 2 moles of nitrogen dioxide

So,

0.6817 mole of copper on reaction forms 2*0.6817 moles of nitrogen dioxide

Moles of nitrogen dioxide = 1.3634 moles

Given:  

Pressure = 724 torr

The conversion of P(torr) to P(atm) is shown below:

P(torr)=\frac {1}{760}\times P(atm)

So,  

Pressure = 724 / 760 atm = 0.9526 atm

Temperature = 28.2 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (28.2 + 273.15) K = 301.35 K  

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9526 atm × V = 1.3634 mol × 0.0821 L.atm/K.mol × 301.35 K  

⇒V = 35.41 L

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