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il63 [147K]
3 years ago
10

Which option supports a theory and allows it to remain the same

Chemistry
2 answers:
mr_godi [17]3 years ago
4 0

Answer:

D.

Explanation:

That would be the last option.

Repeated similar experimental outcomes are confirmation of the theory.

stiv31 [10]3 years ago
4 0

Answer:

Your answer would be D

Explanation:

Repeated experimentation with similar outcomes

This is because a theory is accepted and is allowed to remain the same. Repeated experiments obtain the same results.

Which makes the other options false, development of new techniques, new discoveries and new and revised experimental methods could end with different results. These different results could lead to changes in the theory. Which would make only D correct.

Hope this helps,

Que.

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positive ions are smaller than the ions from which they are formed but negative ions are larger than the is from which they are
Vadim26 [7]
Positive ions are atoms that have lost an electron from its outtermost shell. It is positive because electrons are negative and the loss of something negative makes it a bit more positive.
A negative ion is larger than its original atom because it's gained an electron.

The more electrons an atomic has on its electron cloud, the bigger the atom.

Hopefully I didn't confuse you, good luck. ♡
3 0
3 years ago
Assuming 100% dissociation, calculate the freezing point and boiling point of 1.22 m SnCl₄(aq). Constants may be found here.
Gekata [30.6K]

Answer:

T° freezing solution → -11.3°C

T° boiling solution → 103.1 °C

Explanation:

Assuming 100 % dissociation, we must find the i, Van't Hoff factor which means "the ions that are dissolved in solution"

This salt dissociates as this:

SnCl₄ (aq)  →   1Sn⁴⁺ (aq)  +   4Cl⁻  (aq)   (so i =5)

The formula for the colligative property of freezing point depression and boiling point elevation are:

ΔT = Kf . m . i

where ΔT = T° freezing pure solvent - T° freezing solution

ΔT = Kb . m . i

where ΔT = T° boiling solution - T° boiling pure solvent

Freezing point depression:

0° - T° freezing solution = 1.86°C/m . 1.22 m . 5

T° freezing solution = - (1.86°C/m . 1.22 m . 5) → -11.3°C

Boiling point elevation:

T° boiling solution - 100°C = 0.512 °C/m . 1.22 m . 5

T° boiling solution = (0.512 °C/m . 1.22 m . 5) + 100°C → 103.1 °C

8 0
3 years ago
A gas has a pressure of 500.0 Torr at 35.0 °C. What is the temperature at<br> standard pressure?
Aleks04 [339]

Answer:

466.65 K

Explanation:

Using the formula of  Pressure law,

P/T = P'/T'.................... Equation 1

Where P = Intial pressure of gas, T = Initial temperature of gas, P' = Final pressure of gas, T' = Final temperature of gas.

make T' The subeject of equation 1

T' = (P'T)/P................... Equation 2

From the question,

Given: P = 500 Torr = (500×133.322) N/m² = 66661 N/m², T = 35°C = (35+273) = 308 K, P' = 101000 N/m²( Standard pressure)

Substitute these values into equation 2

T' = (101000×308)/66661

T' = 466.65 K

5 0
3 years ago
This atom tends to gain an electron in its outer shell so that there are a total of 8 electrons.
Archy [21]

oh its a Chlorine isn't it....

it's electronic configuration is

2,8,7

so to make it 8 in its outermost shell it should gain 1 electron...

5 0
3 years ago
As lead chemist for a pharmaceutical manufacturing company, you need to inform the purchasing office of a supply order for the n
Veronika [31]

Answer:

<em>mass of chlorine gas required is 118 kg.</em>

Explanation:

Total mass of the drug (Cisplatin) required = 500 kg

For the drug PtCl2(NH3)2, we first find the molar mass of the compound.

The molar mass of the drug is the total of all the molar mass of the elements in the drug

molar mass of Pt (platinum) in the drug = 195.078 g/mol

molar mass of chlorine (Cl) in the drug = 2 x (35.453 g/mol) = 70.908 g/mol

molar mass of ammonia (NH3) in the drug = 2 x (17.031 g/mol) = 34.062 g/mol

Total molar mass of the drug = 195.078 g/mol + 70.908 g/mol + 34.062 g/mol = 300.048 g/mol

fractional composition of chlorine in the drug = 70.908/300.048 = 0.236

mass of chlorine required for 500 kg of the drug = 0.236 x 500 =<em> 118 kg</em>

6 0
4 years ago
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