Answer:
652.6 g of H₃PO₄ are formed
Explanation:
Reaction is:
P₄O₁₀(s) + 6H₂O(l) → 4H₃PO₄(aq)
As P₄O₁₀ is the reactant in excess, the limiting is water.
Ratio is 6:4. We make a rule of three:
6 moles of water produce 4 moles of phosphoric acid
Therefore, 10 moles of water may prodyce (10 .4) / 6 = 6.66 moles of H₃PO₄
We convert the moles to mass:
6.66 moles . 97.9 g / 1mol = 652.6 g
Answer:
True
Explanation:
True. Metals produces oxides with oxygen
Answer:
it is the formulae of glucose
It is a compound made of carbon,oxygen,hydrogen
Answer:
The correct answer is option C.
Explanation:
![R=\sqrt{x^2+y^2}](https://tex.z-dn.net/?f=R%3D%5Csqrt%7Bx%5E2%2By%5E2%7D)
r = resultant vector
y = vertical component of vector
x = horizontal component of vector
We have :
The vertical component of a vector is 40 N and its horizontal component is 25 N.
x = 25 N
y = 40 N
![R=\sqrt{(25 N)^2+(40 N)^2}](https://tex.z-dn.net/?f=R%3D%5Csqrt%7B%2825%20N%29%5E2%2B%2840%20N%29%5E2%7D)
![R = 47.17 N \approx 47.2 N](https://tex.z-dn.net/?f=R%20%3D%2047.17%20N%20%5Capprox%2047.2%20N)
47.2 N is the magnitude of the vector.
Answer:The dissociation constant of a weak acid is 4.9 ~ 10-8 , its percentage ionization at 0.1 M is ( a ) ... The pH of a 0.1 M aqueous solution of a weak acid ( HA ) is 3.
Explanation:acid. Ka acetic acid = 1.8χ10–5. (b) A buffer solution is prepared by adding 0.10 liter of 2.0 ... Compute the hydrogen ion concentration of the buffer solution.