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Paladinen [302]
2 years ago
10

Suppose you made 40 atoms of Highlinium and it has a

Chemistry
1 answer:
Karo-lina-s [1.5K]2 years ago
6 0

Answer:

After 6sec 5 atoms will be left.

Explanation:

Given data:

Total atoms of Highlinium = 40

Half life = 2 sec

Atoms left after 6sec = ?

Solution:

First of all we will calculate the number of half lives passes during 6sec.

Number of half lives = Time elapsed/ half life

Number of half lives = 6 sec / 2sec

Number of half lives = 3

Now we will calculate the number of atoms left

At time zero = 40 atoms

At 1st half life = 40 atoms/2 = 20 atoms

At 2nd half life = 20 atoms/2 = 10 atoms

At 3rd half life = 10 atoms / 2 = 5 atoms

Thus, after 6sec 5 atoms will be left.

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