Answer:
public String bananaSplit(int insertIdx, String insertText) {
return word.substring(0, insertIdx) + insertText + word.substring(insertIdx);
}
Explanation:
Do you have the other parts of the WordGames class?
Answer:
function createAndFillBufferObject(gl, data) {
var buffer_id;
// Create a buffer object
buffer_id = gl.createBuffer();
if (!buffer_id) {
out.displayError('Failed to create the buffer object for ' + model_name);
return null;
}
// Make the buffer object the active buffer.
gl.bindBuffer(gl.ARRAY_BUFFER, buffer_id);
// Upload the data for this buffer object to the GPU.
gl.bufferData(gl.ARRAY_BUFFER, data, gl.STATIC_DRAW);
return buffer_id;
}
Answer: 83.17
Explanation:
By definition, the dB is an adimensional unit, used to simplify calculations when numbers are either too big or too small, specially in telecommunications.
It applies specifically to power, and it is defined as follows:
P (dB) = 10 log₁₀ P₁ / P₂
Usually P₂ is a reference, for instance, if P₂ = 1 mW, dB is called as dBm (dB referred to 1 mW), but it is always adimensional.
In our question, we know that we have a numerical ratio, that is expressed in dB as 19.2 dB.
Applying the dB definition, we can write the following:
10 log₁₀ X = 19.2 ⇒ log₁₀ X = 19.2 / 10 = 1.92
Solving the logarithmic equation, we can compute X as follows:
X = 10^1.92 = 83.17
X = 83.17
Answer:
There's a parking lot that is 600m² big. The lot must be able to hold at least 3 buses and 10 cars.
Each car takes up 6m² and each bus takes up 30m².
However, there can only be 60 vehicles in the lot at any given time.
The cost to park in the lot is $2.50 per day for cars and $7.50 per day for buses. The lot must make at least $75 each day to break even.
What is a possible car to bus ratio that would allow the lot to make profit?
