Answer:
1.18 is the answer but if u want to round u have the answer as 1.20=1.2
Given P(E) = 0.24 and P(F ∩ E) = 0.17
It says to find conditional probability of F given E has occurred.
We know the formula of conditional probability is given by :-
P(F ║ E) = 
P(F ║ E) = 
= 0.708333
P(F ║ E) = 0.71
Hence, option C i.e. 0.71 is the final answer.
Answer:
0.0016283
Step-by-step explanation:
Given that:
Proportion of defective bulbs, p = 30% = 0.3
Sample size, n = 19 bulbs
Probability that the lot will pass inspection :
P(none of the 19 is defective) Or P(only one of the 19 is defective)
P(none of the 19 is defective) = (1 - p) ^n = (1 - 0.3)^19 ; 0.7^19
0.7^19 = 0.0011398
P(only one of the 19 is defective) :
P(1 defective) * P(18 not defective )
(0.3) * (1 - 0.3)^18
0.3 * 0.7^18
0.3 * 0.001628413597910449 = 0.0004885
Hence,
P(none of the 19 is defective) + P(only one of the 19 is defective)
0.0011398 + 0.0004885) = 0.0016283
Answer:
2.016
Step-by-step explanation:
In your equasion, I couldn't tell if you need to multipy 0.8^2 by 3.15 or are you asking something else? If you want to multiply, the answer is 2.016.
It is not true that is false
