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sattari [20]
4 years ago
7

Please help with all 4 questions give right answer

Mathematics
2 answers:
GarryVolchara [31]4 years ago
8 0
1) Area of the Rectangle = Length * Width
A = 25 * 13
A = 325 in²

2) Area of the Rectangle = bh
A = 823 * 534
A = 439482 Feet²

3) Area of rug = l * w
A = 23 * 234
A = 5382 Yd²

4) Area = 2.7 * 3.9
A = 10.53 Ft²

Hope this helps!

Amiraneli [1.4K]4 years ago
4 0
1)325in^2
2) 439484ft^2
3)5382yd^2
4)10.53ft^2
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3 years ago
Identify the maximum value of the function y = -472 - 24x + -36.
Gnesinka [82]

Answer:

I assume that this is a quadratic equation, something like:

y = -47*x^2 - 24x + (-36)

we can rewrite it as:

y = -47x^2 - 24x - 36

Ok, this is a quadratic equation and we want to find the maximum value.

First, you can notice that the leading coefficient is negative.

This means that the arms of the graph will open downwards.

Then we can conclude that the vertex of the equation is the "higher" point, thus the maximum value will be at the vertex.

Remember that for a general function

y = a*x^2 + b*x + c

the vertex is at:

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So, in our case:

y = -47x^2 - 24x - 36

The vertex will be at:

x = -(-24)/(2*-47) = -12/47

So we just need to evaluate the function in this to find the maximum value.

Remember that "evaluating" the function in x = -12/47 means that we need to change al the "x" by the number (-12/47)

y = -47*(-12/47)^2 - 24*(-12/47) - 36

y = -32.94

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8 0
3 years ago
How can i get 40 for the numbers 5,4,3,2,1
MariettaO [177]

Answer:

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Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
It takes 3 tractors 2 hours to plow a square field whose side is 600 meters. find the number of hours it would take 5 tractors t
NeTakaya

Answer:

5 tractors can plow a square field of side length 1,000 meters in 3.33 hours (3 hours 20 minutes)

Step-by-step explanation:

Let's find out how much each tractor can plow each hour.

\frac{600^{2} }{3*2}=60,000m^{2} per tractor per hour

1,000^{2}=1,000,000m^{2} is the area of the field of side length 1,000 meters

5 tractors can plow 300,000m^{2} per hour.

\frac{1,000,000}{300,000}=3.33 hours

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PilotLPTM [1.2K]

answer 40

Step-by-step explanation:

because you added all together to make one

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