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3 years ago

5

Can someone find the perimeter of JKL pls

1 answer:

Juli2301 [7.4K]3 years ago

5 0

The perimeter should be about 66

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Will mark brainliest! Please help!

ValentinkaMS [17]

Answer:

The dimensions are:

$3(2x+1)$ by $(7x+5)$

Step-by-step explanation:

The area of the rectangle is given as

$A=42x^2+51x+15$

The factored form of this quadratic trinomial gives the dimensions of the rectangle.

We factor 3 first to obtain;

$A=3(14x^2+17x+5)$

We split the middle term to get;

$A=3(14x^2+10x+7x+5)$

We factor within the parenthesis to get;

$A=3(2x(7x+5)+1(7x+5))$

We factor further to get;

$A=3(2x+1)(7x+5)$

The dimensions are:

$3(2x+1)$ by $(7x+5)$

Then the perimeter will be

$2(6x+3+7x+5)=26x+16\:\:\:\boxed{\sqrt{} }$

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3 years ago

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Fantom [35]

0.85 is between 0.8 and 0.9

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Alika [10]

Answer:

the area sector is 123.2

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3 years ago

What is the surface area of a rectangular prism that has i height of 2 length of 5 and width of 13

BaLLatris [955]

Answer:

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Step-by-step explanation:

A=2(wl+hl+hw)

2·(13·5+2·5+2·13)=202

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3 years ago

(x^4+15x^3-77x^2+13x-36)+(x-4)

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4 years ago

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