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DiKsa [7]
3 years ago
12

During 2005, a company produced an average of 2,000 products per month. How many products will the company need to produce from

2006 through 2008 in order to increase its monthly average for the period from 2005 through 2008 by 200% over its 2005 average?
Mathematics
1 answer:
Svet_ta [14]3 years ago
3 0

Answer:

The company needs to produce 264,000 units from 2006 through 2008.

Step-by-step explanation:

Let x represent units produced by company from 2006 to 2008.

We have been given that during 2005, a company produced an average of 2,000 products per month.

The total units produced by company in 2005 would be 12\times 2,000=24,000 units.

The total units produced by company from 2005 to 2008 would be x+24,000 units.

The average of units produced during four years would be total units (x+24,000) divided by total years (4) that is \frac{x+24,000}{4}

We are told that the average of the 4 years should be 200% more than in 2005. Let us find average for 4 years as:

24,000+24,000\times \frac{200}{100}\\\Rightarrow 24,000+24,000\times 2\\=24,000+48,000\\=72,000

We can represent all this information in an equation as:

\frac{x+24,000}{4}=72,000

\frac{x+24,000}{4}*4=72,000*4

x+24,000=288,000

x+24,000-24,000=288,000-24,000

x=264,000

Therefore, the company needs to produce 264,000 units from 2006 through 2008.

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Step-by-step explanation:

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Slope equals rise over run:

The line goes up 10 and moves right 5

10/5 = 2

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Answer:

30 m

Step-by-step explanation:

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dedylja [7]

Hi student, let me help you out! :)

..............................................................................................................................................

We are asked to find the equation of the line, using the given information:

\star~\mathrm{-3}, which is the slope

\star~\mathrm{(1,2)} which is a point that the line contains

\triangle~\fbox{\bf{KEY:}}

  • The slope is the number before x, in the form \mathtt{y=mx+b}.

Since "m" is the slope, and we're given what the slope is, we can substitute -3 for m:

\dag~\mathtt{y=-3x+b}

|||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||

Now, we need to find the y intercept, "b", of the line.

Here's how it's done:

Remember the point that the line contains, (1,2)?

Well, its y-coordinate is 2; so what we do is substitute 2 for y:

\dag~\mathtt{2=-3x+b}

Also, its x-coordinate is 1, so we substitute 1 for x:

\dag~\mathtt{2=-3(1)+b}

Now, solve for b:

\dag~\mathtt{2=-3+b}

Add 3 to both sides:

\dag~\mathtt{2+3=b}

Thus, we have

\dag~\mathtt{5=b}

Thus, the equation of the line is:

\bigstar\underline{\boxed{\mathtt{y=-3x+5}}}

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

\overline{\underline{~~~~~~~~~~~~~~~~~~~~~~~~~~}}

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