Answer:
The volume will be occupied is 244, 36L.
Explanation:
We convert the unit of temperature to celsius into Kelvin, then use the ideal gas formula, solve for V (volume) and use the gas constant R =0.082 l atm / K mol:
0°C=273K 25°C= 273 + 25=298K
PV=nRT ---> V=nRT/P
V= 5,00 mol x 0,082 l atm/ K mol x 298 K/0,500 atm
<em>V=244,36L</em>
Answer:
a. 5.9 × 10⁻³ M/s
b. 0.012 M/s
Explanation:
Let's consider the following reaction.
2 N₂O(g) → 2 N₂(g) + O₂(g)
a.
Time (t): 12.0 s
Δn(O₂): 1.7 × 10⁻² mol
Volume (V): 0.240 L
We can find the average rate of the reaction over this time interval using the following expression.
r = Δn(O₂) / V × t
r = 1.7 × 10⁻² mol / 0.240 L × 12.0 s
r = 5.9 × 10⁻³ M/s
b. The molar ratio of N₂O to O₂ is 2:1. The rate of change of N₂O is:
5.9 × 10⁻³ mol O₂/L.s × (2 mol N₂O/1 mol O₂) = 0.012 M/s
C₀=8.10M
c₁=5.28M
v₀=1.58 L
v₁-?
n=c₀v₀=c₁v₁
v₁=c₀v₀/c₁
v₁=8.10*1.58/5.28=2.42 L
I can’t answer you but here have a meme
