The particles that combined in the middle of the structure best describes neutron as neutron is always present in the middle of atomic structure
Answer:
b) 49.48% C, 5.19% H, 28.85% N, and 16.48% O
Explanation:
we find the mass for each element in one mole by multiplying the number of atoms in one molecule with the atomic mass
mC=8Ac=8*12=96g
mH=10AH=10*1=10g
mN=4AN=4*14=56g
mO=2AO=2*16=32g
by adding the masses together we find the molar mass of the molecule
M=mC+nH+mN+mO=96+10+56+32=194g/mole
we apply the rule of threes to find the percentage of each element
194g..96gC..10gH...56gN....32gO
100g....a...........b...........c.............d
a=(100*96)/194=49.48%C
b=(100*10)/194=5.19%H
c=(100*56)/194=28.85%N
d=(100*32)/194=16.48%O
Answer: 
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products must be same as the mass of reactants.
For the conservation of mass, the number of atoms of each element must be same in reactants and products. Thus we need to balance the reaction by writing appropriate stochiometric coefficients.
All the hydrocarbons burn in oxygen to form carbon dioxide and water.Thus the complete balanced equation is:

The primary distinction between the digestive systems of cows and humans is that the former uses a foregut fermenter while the latter uses a straightforward monogastric digestion. The types of teeth, mouths, stomachs, guts, and digestive enzymes released by the gut also vary between the two digestive systems. Cows and humans have different digestive systems because they have evolved two different sorts of dietary patterns based on their capacities. The primary distinctions between the digestive systems of cows and humans are in the types of teeth, mouths, stomachs, and intestines, as well as the enzymes released.
1) since we are given percentages, we can assume we have 100 grams of the molecule.
55.6 % Cu ----> 55.6 grams Cu
16.4 % Fe------> 16.4 grams Fe
28.0% S--------> 28.0 grams S
2) convert each gram to moles using the molar masses given



3) we divide the smallest value of moles (0.293) to each one.
Cu --> 0.876 / 0.293= 3
Fe---> 0.293 / 0.293= 1
S-----> 0.875 / 0.293= 3
4) let's write the empirical formula
Cu₃FeS₃