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kvasek [131]
2 years ago
8

You are studying a metabolic enzyme that is found in organisms living at extremely high temperatures and an acidic environment.

You carry out your reactions on your lab bench at room temperature in water and find that the reaction is quite slow, even though you are able to reach a Vmax. Which of the following is not a good way to increase the rate of the reaction?
A) Add more enzyme to the reaction.
B) Increase substrate concentration.
C) Decrease the pH of the reaction solution.
D) Increase the temperature.

Biology
2 answers:
oksano4ka [1.4K]2 years ago
7 0

Answer:

B) Increase substrate concentration.

Explanation:

As the organism is living in environment with high temprature and (acidic) low pH the enzymes are affected as follows :

<u>Increased Temprature : </u>Initially the rate of reaction increase (10 degrees rise in T causes 50 to 100% rise in activity of enzyme)  but ultimately over the period of time enzymes become denatured , hence they cannot stimulate the rate of reaction even if the substrates are added.

<u>Effect of pH: </u>pH is the factor of stability of the enzymes but if the pH becomes extremely low or high the activity of enzymes is affected in such a way resulting in complete loss of activity of enzyme hence addtion of substrates can't increase the activity.

Thus among the given options , option B is the right choice as the increase in the substrate won't increase the activity of the enzyme as they are already denatured.

gulaghasi [49]2 years ago
3 0

Answer:

Increasing the substrate concentration.

Explanation:

Increasing the substrate concentration can increase the rate of the reaction to a certain point. However, once all of the enzymes bounded to the substrate, any further addition of it will not be going to affect or increase the rate of the reaction at all, as all the enzymes will be saturated and working in their maximum rates.

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4 0
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If 32 packed volume units of cells are separated from 46 volume units of plasma from a blood sample, the haematocrit is _______
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Answer:

If 32 packed volume units of cells are separated from 46 volume units of plasma from a blood sample, the hematocrit is <u>41,02%</u> percent. The hematocrit value is <u>within the normal</u> range.

Explanation:

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Hematocrit (or packed cell volume -PCV-)is defined as the percentage of red blood cells (vol%) in a blood sample. One common method of determining it is by centrifuging a heparinized blood sample in a capillary tube at 10 000 RPM for five minutes. This separates the blood sample in two layers, formed elements (RBC and WBC) and Plasma.

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The hematocrit can be calculated as the volume of packed cells divided by the total volume of the blood sample.

\frac{PCV}{TOTAL(pcv+plasma} * 100

<u>In the question:</u>

\frac{32}{32+46} * 100 = \frac{32}{78} * 100 = 41,02%

In humans the normal hematocrit range is 40,7% to 50,3% for men and 36,1% to 44,3%. Taking these reference values into consideration, this sample is within the normal range.

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