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babymother [125]
3 years ago
5

You can fly from Seattle to Boise for $137.50, from Boise to Witchita for $92.50 and from Witchita to Austin for $162.50. Use me

ntal math to find the total cost of the flight from Seattle to Austin.
Mathematics
2 answers:
Vesnalui [34]3 years ago
6 0
<span>We add all these numbers up. 137.50 +162.50+92.50= 392.50$ Use a cacl or by hand</span>
Katen [24]3 years ago
4 0

Answer:

$392.50 is the sum

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Peter has a coupon for 15% off the price of any item in a sporting good store he wants to buy a pair of sneakers that are priced
aniked [119]

Answer:

$31.44

Step-by-step explanation:

According to the word problem, Peter has a coupon for 15% OFF.

This means the price will reduce by 15%.

To solve this, first, change the percentage (15%) to decimal form.

To do this, divide the percentage by 100.

15 / 100 = 0.15.

0.15 is the decimal form of 15%.

Next, multiply the decimal form of the percentage by the price.

36.99 x 0.15 = 5.5485

Lastly, subtract the product from the original price.

36.99 - 5.5485 = 31.4415

In this case, the product goes above the hundredths place.

So we must round 31.4415 to the hundredths place.

31.4415 ≈ 31.44

Therefore, the sneakers are $31.44 after the discount of 15%.

7 0
3 years ago
Kevin won two goldfish at the county fair. He put them in a bowl with 2 liters of water. The next day, he bought a fish tank tha
allochka39001 [22]

Answer:

UDCVUEGBCYEJJAJAJ

Step-by-step explanation:

7 0
4 years ago
The Wall Street Journal reported that Walmart Stores Inc. is planning to lay off employees at its Sam's Club warehouse unit. App
tatyana61 [14]

Answer:

a) \bar X = 52

Median = 55

b) Q_1= \frac{44+44}{2}=44

Q_3= \frac{57+60}{2}=58.5

c) Range = Max -Min = 69-36=33

d) s^2 =100.1429

s= \sqrt{100.143}=10.0071

e) Lower = Q_1 -1.5 IQR = 44-1.5(58.5-44) = 22.25

Upper = Q_1 +1.5 IQR = 44+1.5(58.5-44) = 65.75

A possible outlier would be the value of 69 since its above the upper limti for the boxplot.

Step-by-step explanation:

For this case we have the following dataset:

55 56 44 43 44 56 60 62 57 45 36 38 50 69 65

A total of 15 observations

Part a

We calculate the mean with the following formula:

\bar X = \frac{\sum_{i=1}^{15} X_i}{15}

And for this case we got \bar X = 52

For the median we ust need to order the data on increasing way like this:

36, 38,43,44,44,45,50,55,56,56,57,60,62,65,69

Since the number of observations is an odd number the median would be on the 8 position from the dataset ordered on this case:

Median = 55

Part b

In order to calculate the Q1 we need to select the following data:

36, 38,43,44,44,45,50,55

And the Q1 would be the average between the 4 and 5 positions like this:

Q_1= \frac{44+44}{2}=44

And for the Q3 we select these values:

55,56,56,57,60,62,65,69

And the Q3 would be the average between the 4 and 5 positions like this:

Q_3= \frac{57+60}{2}=58.5

Part c

The Range is defined as:

Range = Max -Min = 69-36=33

Part d

In order to calculate the sample variance we can use the following formula:

s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

And if we replace we got:

s^2 =100.1429

And the deviation is just the square root of the variance:

s= \sqrt{100.143}=10.0071

Part e

For this case we need to find the lower and upper limits for the boxplot given by:

Lower = Q_1 -1.5 IQR = 44-1.5(58.5-44) = 22.25

Upper = Q_1 +1.5 IQR = 44+1.5(58.5-44) = 65.75

A possible outlier would be the value of 69 since its above the upper limti for the boxplot.

4 0
4 years ago
What is the total area? Use 3 for Pi.<br> answer fast pls! xx
klemol [59]

Answer:

146.3m²

Step-by-step explanation:

area of quarter circle=1/4π×8²

=50.3m²

area of the square=s²

8×8=64m²

area of the triangle=1/2bh

1/2×8×8=32m²

total area=50.3+64+32=146.3m²

3 0
3 years ago
The observations of 124.53, 124.55, 142.51, and 124.52 are obtained when taping the length of a line. What should the observer c
mylen [45]

Answer: the observer should consider to eliminate or to retake the third measure.

Explanation:

The four measures taken are 124.53, 124.55, 142.51 and 124.52.

As it can be easily seen, the third measure is much different from the other three. This means that something went wrong during the observation: it can be either the measure taken wrong or that the number was written wrong (if you switch the 2 and the 4 you get a number similar to the other ones).

If the third measure is not considered, an estimate of the mean would place it around 124.5, while if the outlier (the detatched number) is considered an estimate of the mean would increase to about 129.

Therefore, in order to obtain a more reliable mean, the observer should consider to eliminate or to retake the third measure.

6 0
3 years ago
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