All categories

3 years ago

Complete the equation so that it has solutions of –5 and 7 x2 + x + = 0

Mathematics

2 answers:

Mkey [24]3 years ago

5 0

Step-by-step explanation:

${x}^{2} + ( - 5 + 7)x + ( - 5) \times 7 = 0 \\ {x}^{2} + 2x - 35 = 0$

Katarina [22]3 years ago

4 0

Answer:

-2x, -35

x2 + -2x + -35 = 0

Step-by-step explanation:

You might be interested in

prove that the sum of two consecutive exponents of the number 5 is divisible by 30. If N ia the smaller of two consecutive expon

kotykmax [81]

Answer:

5^n-1

Step-by-step explanation:

5^n-1*30

3 0

2 years ago

12x+34>140 solve for x

Harlamova29_29 [7]

Answer:

x>\frac{53}{6}

Step-by-step explanation:

12x>140−34

2 Simplify 140-34140−34 to 106106.

12x>106

3 Divide both sides by 1212.

x>\frac{106}{12}

7 0

2 years ago

What are the first five multiples of seven

Mkey [24]

7,14,21,28,35
Multiply 7 by 1-5

7 0

3 years ago

Read 2 more answers

Determine if the sides are greater than (>), less than (<), or equal (=) to each other.

DochEvi [55]

In ∆BCE

$\\ \sf\longmapsto$

Opposite side to <E=BC

Opposite side to <B=EC

<E=<B

$\\ \sf\longmapsto BC=EC$

4 0

2 years ago

Let the probability of success on a Bernoulli trial be 0.26. a. In five Bernoulli trials, what is the probability that there wil

andreyandreev [35.5K]

Answer:

0.3898 = 38.98% probability that there will be 4 failures

Step-by-step explanation:

A sequence of Bernoulli trials forms the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Let the probability of success on a Bernoulli trial be 0.26.

This means that $p = 0.26$

a. In five Bernoulli trials, what is the probability that there will be 4 failures?

Five trials means that $n = 5$

4 failures, so 1 success, and we have to find P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{5,1}.(0.26)^{1}.(0.74)^{4} = 0.3898$

0.3898 = 38.98% probability that there will be 4 failures

4 0

2 years ago

Complete the equation so that it has solutions of –5 and 7 x2 + __ x +__ = 0

Complete the equation so that it has solutions of –5 and 7 x2 + x + = 0