Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.
<h3>What is the binomial distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- 0.54% of the calls receive a busy signal, hence p = 0.0054.
- A sample of 1300 callers is taken, hence n = 1300.
The probability that at least 5 received a busy signal is given by:

In which:
P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).
Then:






Then:
P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.

0.8295 = 82.95% probability that at least 5 received a busy signal.
More can be learned about the binomial distribution at brainly.com/question/24863377
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Answer: The distance between the two points is 13.
Hey there!
Okay, so when you get a problem like this, all you need to do in insert the given value into the function and solve.
For example:
As you can see, they state that <em>(a) = 27, </em>so you insert 27 in for a in the function and it will look like this:
h(27) = 3(27) + 5
Now you solve on the right side of the equal sign:
3(27) = 81 (you multiply them)
81 + 5 = 86
When you plug the value of 27 in for a in this function, your output is equal to 86.
I think it is 8/17...
hope this helps!
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