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siniylev [52]
3 years ago
11

robert plant 7 trees behind westwood school. he planted 6 times as many trees in front of the school. how many trees did he plan

t?
Mathematics
2 answers:
Sati [7]3 years ago
4 0
49 in total or 42 trees in the front

Verdich [7]3 years ago
3 0
42 in front and 49 in total.
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What is the median number of points scored by the two players. WILL GIVE BRAINLY.
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Step-by-step explanation:

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To solve both of these expressions, we want to add or subtract from left to right.

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5 0
4 years ago
When the sample size and the sample proportion remain the same, a 90 percent confidence interval for a population proportion p w
deff fn [24]

Answer:

A 90% confidence interval for <em>p</em> will be <u>narrower </u>than the 99% confidence interval.

Step-by-step explanation:

The formula to compute the (1 - <em>α</em>) % confidence interval for a population proportion is:

CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

Here \hat p is the sample proportion.

The margin of error of the confidence interval is:

MOE= z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The MOE is dependent on:

  1. Confidence level
  2. Standard deviation
  3. Sample size

The MOE is directly related to the confidence level and standard deviation.

So if any of the two increases then the MOE also increases, thus widening the confidence interval.

And the MOE is inversely related to the sample size.

So if the sample increases the MOE decreases and vice versa.

It is provided that the sample size and the sample proportion are not altered.

The critical value of <em>z</em> for 90% confidence level is:

z_{\alpha/2}= z_{0.10/2}=z_{0.05}=1.645

And the critical value of <em>z</em> for 99% confidence level is:

z_{\alpha/2}= z_{0.05/2}=z_{0.05}=1.96

So as the confidence level increases the critical value increases.

Thus, a 90% confidence interval for <em>p</em> will be narrower than the 99% confidence interval.

6 0
3 years ago
I need help on this please
arsen [322]

Answer:

P(compact cars) = 4/25 or .16

Step-by-step explanation:

<em>We know that there are </em><em>13 trucks, 8 vans, and 4 compact cars.</em>

<em />

<em>Let </em><em>P </em><em>denotes the probability of an event</em>

<em />

<em>Now we are asked to find the probability of compact cars</em>

<em />

<em>Number of favorable events = number of compact cars = 4</em>

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<em>total number of outcomes </em><em>= 13+8+4 = 25</em>

<em>hence, P(compact cars) = number of favorable events/total outcomes</em>

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4 0
4 years ago
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