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3 years ago

If f (x) = 2 x + 5 and three-halves are inverse functions of each other and f(x)=2x+5, what is f-1(8)?

Mathematics

1 answer:

nalin [4]3 years ago

6 0

Answer:

Found the answer, its B. 3/2!

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For the Data Set below, calculate the Variance to the nearest hundredth decimal place. (Do not use a coma in your answer) 175 34

dlinn [17]

Answer:

The variance of the data is 29966.3.

Step-by-step explanation:

The given data set is

175, 349, 234, 512, 638, 549, 500, 611

We need to find the variance to the nearest hundredth decimal place.

Mean of the data

$Mean=\dfrac{\sum x}{n}$

where, n is number of observation.

$Mean=\dfrac{3568}{8}=446$

The mean of the data is 446.

$Variance=\dfrac{\sum (x-mean)^2}{n-1}$

$Variance=\dfrac{(175-446)^2+(349-446)^2+(234-446)^2+(512-446)^2+(638-446)^2+(549-446)^2+(500-446)^2+(611-446)^2}{8-1}$

$Variance=\dfrac{209764}{7}$

$Variance=29966.2857$

$Variance\approx 29966.3$

Therefore, the variance of the data is 29966.3.

4 0

3 years ago

Find the lateral surface area

Lena [83]

Answer:

At first find the Shaded area of picture

Then calculate area of picture

And find the lateral area

4 0

3 years ago

vanessa invested $2,500 into an account that will increase in value by 3.5% each year. Write an exponential function to model th

astraxan [27]

Answer: (i) A = 2500 ( $(1.035)^{n}$

(ii) A =$ 4,974.47

Step-by-step explanation:'

The exponential function is given as :

A = P $(1+r)^{n}$

Where :

A = amount

P = principal

r = rate %

n = number of years

substituting , the exponential function to model the situation becomes

A = 2500 ( $(1.035)^{n}$

(ii) when n = 20 , the Amount becomes

A = 2500( $(1.035)^{20}$

A =$ 4,974.47

4 0

3 years ago

Find the minimum distance between the point (-3,2) and the line y = -x + 1

Natasha2012 [34]

The minimum distance between the point(-3,2) and the line y = -x + 1 is $\sqrt{2}$ units.

<h3>What is a line segment?</h3>

The line that joins two points on a cartesian plane is a line segment.

Analysis:

The formula for calculating distance between a line and a point is

d = $\frac{Ax1 + By1 + c}{\sqrt{A^{2} + B^{2} } }$

where A = coefficient of x term of the line, B = coefficient of y in the line and C is the constant term of the line.

x1 and y1 are coordinates of the point.

for the line y = -x + 1 which is = y + x -1 = 0, A = 1, B = 1, C = -1, x1 = -3, y = 2
d = $\frac{1(-3) + 1(2) + (-1)}{\sqrt{(-3)^{2} + 2^{2} } }$ = $\sqrt{2}$ units

In conclusion, the distance between the point and the line is $\sqrt{2}$ units

Learn more about distance between line segments: brainly.com/question/2437195

#SPJ1

4 0

2 years ago

Will give brainliest! please help!

lana [24]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers