The average rate of change of on the interval [a,b] is:
f(b)−f(a)/ b-a
or
y1-y2/x1-x2 which is how I learned it, average ratw of change is just slope
so you would plug your numbers into x
1st the b: 6((1))^2+31((1))-12
=6+31-12 1^2=1, so it cancels
f(b) =25
2nd the a: 6((-2))^2+31((-2))-12
=6(4)+31(-2)-12
=24+-62-12
f(a) =-50
3rd plug them in: (25- -50)÷(1-(-2)
=75÷3
=25
so your average rate of change(or slope) is 25 :)
Answer:
angle M
Step-by-step explanation:
if you are using side angle side the two sides may be
line LK and NK
and angle M
--First we have to simplfy
--Cancel common factors
--Here remember never cancel factors in a subtraction or addition problem
--Now Multiply each side until both denominators are equal to each other
![\frac{2[x(x+1)]}{x(x+3)(x+1)} -\frac{(x-3)(x+3)}{x(x+3)(x+1)}](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Bx%28x%2B1%29%5D%7D%7Bx%28x%2B3%29%28x%2B1%29%7D%20-%5Cfrac%7B%28x-3%29%28x%2B3%29%7D%7Bx%28x%2B3%29%28x%2B1%29%7D)
--Simplify
--Now that the denominators are the same: subtract!
--And LAST STEP! ......Simplify More.... To get your answer
Answer:
Dividing 4x^2 - 13x + 8 by x + 5 or x - (-5), in synthetic division form:
-5) 4 | -13 | 8
↓ 4 x (-5) (-5) x (-33)
4 -33 173
=> Quotient is 4x - 33 and remainder is 173
=> (4x^2 - 13x + 8)/(x + 5) = (4x - 33) + 173/(x + 5)
Hope this helps!
:)
3x-x=(2x+4)-(x+4)? That is my answer but it might not be right
