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3 years ago

electrons do not follow specific paths, so describing the area where an electron is likely to be is more scientifically accurate

Chemistry

1 answer:

r-ruslan [8.4K]3 years ago

3 0

Answer:

Electrons do not follow specific paths, so the area in which an electron is more scientifically accurate is at the orbitals.

Explanation:

As we know in an atom various electrons are present, they are filled in the orbitals in order to decrease the energy of the atom. These electrons inside the orbitals are arranged from smaller to larger. The lowest one is filled first, the order in which energy is filled is like 1s, 2s, 2p,3s3p,4s,3d etc. The electrons that present far away from the nucleus have the highest energy, the electrons present in the first orbital from the nucleus hold less energy.

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1) A light bulb takes in 30 of energy per second. It transfers 3j as use

natta225 [31]

Answer:

$\boxed{\text{10 \%}}$

Explanation:

The formula for efficiency is

$\begin{array}{rcl}\text{Efficiency} & = & \dfrac{\text{useful energy out}}{\text{energy in}} \times 100 \,\% \\\\\eta & = & \dfrac{w_{\text{out}}}{w_{\text{in}} } \times 100 \,\%\\\end{array}$

Data:

Useful energy = 3 J

Energy input = 30 J

Calculation:

$\begin{array}{rcl}\eta & = & \dfrac{\text{3 J}}{\text{30 J}} \times 100 \,\%\\\\\eta & = & 10 \, \%\\\end{array}\\\text{ The efficiency is }\boxed{\textbf{10 \%}}$

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3 years ago

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3 years ago

What is the concentration of a potassium iodate solution after you complete the following porcedure? Pipette 10 mL of a 0.31 M p

zubka84 [21]

<u>Given:</u>

Initial concentration of potassium iodate (KIO3) M1 = 0.31 M

Initial volume of KIO3 (stock solution) V1 = 10 ml

Final volume of KIO3 V2 = 100 ml

<u>To determine:</u>

The final concentration of KIO3 i.e. M2

<u>Explanation:</u>

Use the relation-

M1V1 = M2V2

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3 years ago

If we start with 8000 atoms of radium-226 how much would remain after 3200 years?

olya-2409 [2.1K]

<h3>Answer:</h3>

2000 atoms

<h3>Explanation:</h3>

We are given the following;

Initial number of atoms of radium-226 as 8000 atoms

Time taken for the decay 3200 years

We are required to determine the number of atoms that will remain after 3200 years.

We need to know the half life of Radium

Half life is the time taken by a radio active material to decay by half of its initial amount.

Half life of Radium-226 is 1600 years

Therefore, using the formula;

Remaining amount = Original amount × 0.5^n

where n is the number of half lives

n = 3200 years ÷ 1600 years

= 2

Therefore;

Remaining amount = 8000 atoms × 0.5^2

= 8000 × 0.25

= 2000 atoms

Thus, the number of radium-226 that will remain after 3200 years is 2000 atoms.

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3 years ago

How did electrons gain energy in order to jump to higher energy levels?

Alla [95]

Answer: An electron will jump to a higher energy level when excited by an external energy gain such as a large heat increase or the presence of an electrical field, or collision with another electron.

Explanation:

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3 years ago