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2 years ago

14

Draw the electron dot structure for the hydrogen carbonate ion hco3-. Carbon is the central atom, and hydrogen is attached to ox

ygen in this polyatomic anion.

1 answer:

Anna11 [10]2 years ago

5 0

Explanation:

this is your answer hope it will help you

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Read this sentence from Chapter One of Jack London’s The Call of the Wild.

xenn [34]

Answer:

b)

Explanation:

It shows the natrual proggresion of a story and helps blend the narrtive together.

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2 years ago

Read 2 more answers

What is the equations that decompose hydrogen peroxide

Rufina [12.5K]

2H2O2 decomposes into the products 2H2O + O2(g)

5 0

3 years ago

CO2(g)+CCl4(g)⇌2COCl2(g) Calculate ΔG for this reaction at 25 ∘C under these conditions: PCO2PCCl4PCOCl2===0.140 atm0.185 atm0.7

padilas [110]

<u>Answer:</u> The $\Delta G$ for the reaction is 54.425 kJ/mol

<u>Explanation:</u>

For the given balanced chemical equation:

$CO_2(g)+CCl_4(g)\rightleftharpoons 2COCl_2(g)$

We are given:

$\Delta G^o_f_{CO_2}=-394.4kJ/mol\\\Delta G^o_f_{CCl_4}=-62.3kJ/mol\\\Delta G^o_f_{COCl_2}=-204.9kJ/mol$

To calculate $\Delta G^o_{rxn}$ for the reaction, we use the equation:

$\Delta G^o_{rxn}=\sum [n\times \Delta G_f(product)]-\sum [n\times \Delta G_f(reactant)]$

For the given equation:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(COCl_2)})]-[(1\times \Delta G^o_f_{(CO_2)})+(1\times \Delta G^o_f_{(CCl_4)})]$

Putting values in above equation, we get:

$\Delta G^o_{rxn}=[(2\times (-204.9))-((1\times (-394.4))+(1\times (-62.3)))]\\\Delta G^o_{rxn}=46.9kJ=46900J$

Conversion factor used = 1 kJ = 1000 J

The expression of $K_p$ for the given reaction:

$K_p=\frac{(p_{COCl_2})^2}{p_{CO_2}\times p_{CCl_4}}$

We are given:

$p_{COCl_2}=0.735atm\\p_{CO_2}=0.140atm\\p_{CCl_4}=0.185atm$

Putting values in above equation, we get:

$K_p=\frac{(0.735)^2}{0.410\times 0.185}\\\\K_p=20.85$

To calculate the gibbs free energy of the reaction, we use the equation:

$\Delta G=\Delta G^o+RT\ln K_p$

where,

$\Delta G$ = Gibbs' free energy of the reaction = ?

$\Delta G^o$ = Standard gibbs' free energy change of the reaction = 46900 J

R = Gas constant = $8.314J/K mol$

T = Temperature = $25^oC=[25+273]K=298K$

$K_p$ = equilibrium constant in terms of partial pressure = 20.85

Putting values in above equation, we get:

$\Delta G=46900J+(8.314J/K.mol\times 298K\times \ln(20.85))\\\\\Delta G=54425.26J/mol=54.425kJ/mol$

Hence, the $\Delta G$ for the reaction is 54.425 kJ/mol

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3 years ago

What is the broadest, most general level of taxonomy?

nikdorinn [45]

Answer:The levels of classification are as follows (Broadest to

narrowest): Domain, Kingdom, Phylum, Class, Order, Family, Genus,

Species

Explanation:

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3 years ago

SEP Develop Models Each helium atom has two protons. Sketch models

RSB [31]

Protons and neutrons are located in the nucleus of the atom while the electrons move in the trajectory of the shell

<h3>Further explanation </h3>

Isotopes are atoms whose no-atom has the same number of protons while still having a different number of neutrons.

So Isotopes are elements that have the same Atomic Number (Proton)

Isotopes of Helium : helium-3 and helium-4

₂³He :

protons = 2

electrons=protons=2

neutron=mass number-atomic number=3-2=1

₂³He :

protons = 2

electrons=protons=2

neutron=mass number-atomic number=3-2=1

₂⁴He

protons = 2

electrons=protons=2

neutron=mass number-atomic number=4-2=2

Protons and neutron in the nucleus, electrons in the shell

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3 years ago