The three sides of a triangle are n, 3n+3, and 2n+11. If the perimeter of the triangle is 50 inches, what is the length of each

Question

Tresset [83]

2 years ago

15

The three sides of a triangle are n, 3n+3, and 2n+11. If the perimeter of the triangle is 50 inches, what is the length of each

side?

Mathematics

1 answer:

mylen [45] · Answer 1 · 2023-01-27T09:15:35+03:00

Answer:

6, 21, and 23 inches

Step-by-step explanation:

The perimeter of a triangle is equal to the sum of all side lengths in that triangle. We're given the perimeter as 50 inches, and the side lengths as n, 3n + 3, and 2n + 11.

This means that we can algebraically solve the equation $n + 3n + 3 + 2n + 11 = 50$

Step 1: Combine like terms.

$(n+3n+2n) + (3+11) = 50$
$6n + 14 = 50$

Step 2: Subtract 14 from both sides.

$6n + 14 - 14 = 50 - 14$
$6n = 36$

Step 3: Divide both sides by 6.

$6n/6 = 36/6$
$n = 6$

Step 4: Plug in the value of n as 6 in each side.

$(6) + (3(6) + 3) + (2(6)+11) = 50$
$(6) + (18+3) + (12+11) = 50$
$(6) + (21) + (23) = 50$

Therefore, the side lengths are 6, 21, and 23 inches.

Have a lovely rest of your day/night, and good luck with your assignments! ♡