Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, ![[ab]_K](https://tex.z-dn.net/?f=%20%5Bab%5D_K%20)
is equal to ![[ba]_K](https://tex.z-dn.net/?f=%20%5Bba%5D_K%20)
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, ![[ab]_H = [ba]_H](https://tex.z-dn.net/?f=%20%5Bab%5D_H%20%3D%20%5Bba%5D_H%20)
. Since a and b were generic elements of H, then H/G is abelian.
Answer:
(x, y) = (3, 3)
Step-by-step explanation:
Subtract double the second equation from the first.
(2x +3y) -2(x +y) = (15) -2(6)
y = 3 . . . . . . . . simplify
Use the second equation to find x.
x = 6 -y = 6 -3 = 3
The values of x and y are both 3.
It would take them 120 hours to get to the same point on the path again.
Kara is traveling at half the speed of Steven. Therefore, we Steven finishes his second lap Kara will just be finishing her first lap. They will both be at the starting lap again.
It will take Kara 120 hours to complete the lap.
1800 / 15 = 120
(That is a lot of time, do you have the numbers correct?)
Answer
6.9
Step-by-step explanation:
gave up on deltamath
