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2 years ago

Fint the center circle with these coordnates (10,3)(3,10)and(-4,3

1 answer:

4 0

The length of the line joining the center of the circle and each coordinate is equal.
Let the center of the circle be (a, b), then
(a - 10)^2 + (b - 3)^2 = (a - 3)^2 + (b - 10)^2 = (a + 4)^2 + (b - 3)^2
a^2 - 20a + 100 + b^2 - 6b + 9 = a^2 - 6a + 9 + b^2 - 20b + 100 = a^2 + 8a + 16 + b^2 - 6b + 9

a^2 - 20a + 100 + b^2 - 6b + 9 = a^2 - 6a + 9 + b^2 - 20b + 100 . . . (1)
a^2 - 20a + 100 + b^2 - 6b + 9 = a^2 + 8a + 16 + b^2 - 6b + 9 . . . (2)

From (1): 14a - 14b = 0 => a = b
From (2): 28a = 84 => a = 84/28 = 3

Therefore, center = (a, b) = (3, 3)

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Net for a cube has a total surface area of 150 in.2. what is the length of one side of a square face

djverab [1.8K]

Surface area of a cube is given by
SA=6a²
but
SA=150 in²
thus
150=6a²
solving for a we obtain:
150/6=a²
a²=25
thus
a=√25
a=5 inches
hence the side length is 5inches

5 0

2 years ago

"If a number divided by 4 leaves remainder 2 or 3", then which one is the correct statement 'n why?

Hoochie [10]

Answer:

As the number is a prime number. Therefore, option 'c' is true.

Step-by-step explanation:

Let us take the number 7 and divide it by 4

$\frac{7}{4}$

We know that

$Quotient\frac{Remainder}{Divisor}$

$\frac{7}{4}=1\frac{3}{4}$

so the remainder is 3. ∵ $Quotient\frac{Remainder}{Divisor}$

As 7 is a prime number, and when we divide the prime number 7 by 4, we get the remainder 3.

Thus, the number is a prime number. Therefore, option 'c' is true.

5 0

2 years ago

SHOW WORK PLEASE IN A TESt!!!

charle [14.2K]

Add 10 to both sides to cancel out the 10
divide 2 on both sides
X= 18

4 0

2 years ago

Stella graphs the equation y=1/3x – 2

faltersainse [42]

we have

$y=\frac{1}{3}x-2$

Statements

case A) The graph is a straight line.

The statement is True

Because, this is a linear equation (see the attached figure)

case B) The line passes through the origin.

The statement is False

Because the point $(0,0)$ is not a solution of the equation

Verify

Substitute the value of x and y in the equation

$0=\frac{1}{3}*0-2$

$0=-2$ ------> is not true

the point $(0,0)$ is not a solution

therefore

The line does not pass through the origin

case C) The line passes through the point $(0,-2)$

The statement is True

Because the point $(0,-2)$ is a solution of the equation

Verify

Substitute the value of x and y in the equation

$-2=\frac{1}{3}*0-2$

$-2=-2$ ------> is true

the point $(0,-2)$ is a solution

therefore

The line passes through the point $(0,-2)$

case D) The slope of the line is $3$

The statement is False

Because, the slope of the line is $m=\frac{1}{3}$

case E) The y-intercept of the line is $2$

The statement is False

we know that

The y-intercept is the value of y when the value of x is equal to zero

For $x=0$

find the value of y

$y=\frac{1}{3}*0-2=-2$

the y-intercept is equal to $-2$

5 0

3 years ago

Read 2 more answers

Solve for x Need help asap

vlabodo [156]

Answer:

$x=55$

Step-by-step explanation:

Corresponding angles of two parallel lines are always equal. The angle on "top" of $2x+6$ corresponds with the angle marked as $x+9$ . Therefore, its measure must also be $x+9$ .