Sometimes, but not every time.
A rhombus can be a square, but it doesn't always have to be.
A square is a rhombus that has special, extra requirements ...
its angles must be 90°. So every square is a rhombus, but
not every rhombus is a square.
Given m<ABC=88°.
<ABD=2x and <CBD=x-2.
Soltution. m<ABC is the sum of angles m<ABD and m<CBD.
So, we can setup an equation as
m<ABD + m<CBD = m<ABC.
Plugging values of m<ABD, m<CBD and m<ABC in above equation, we get
2x + x-2 = 88
Combining like terms 2x+x=3x, we get
3x-2=88.
Adding 2 on both sides,
3x-2+2=88+2.
3x=90.
Dividing both sides by 3, we get
3x/3=90/3
x=30.
Plugging value of x=30 in given values of m<ABD and m<CBD
<ABD=2x = 2(30) = 60° and
<CBD=x-2 = x-2 = 30-2 =28°.
Therefore, <ABD =60° and <CBD=28°.
Answer:
Is f(x)=I x - 2 I the second one
Answer:
Im pretty sure its B for the first one
Step-by-step explanation: