Answer:
other person is correct
Step-by-step explanation:
The <em>quadratic</em> function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).
<h3>How to analyze quadratic equations</h3>
In this question we have a graph of a <em>quadratic</em> equation translated to another place of a <em>Cartesian</em> plane, whose form coincides with the <em>vertex</em> form of the equation of the parabola, whose form is:
g(x) = C · (x - h)² - k (1)
Where:
- (h, k) - Vertex coordinates
- C - Vertex constant
By direct comparison we notice that (h, k) = (5, 1) and C = 1. Now we proceed to check if the points (x, y) = (2, 10) and (x, y) = (8, 10) belong to the parabola.
x = 2
g(2) = (2 - 5)² + 1
g(2) = 10
x = 8
g(8) = (8 - 5)² + 1
g(8) = 10
The <em>quadratic</em> function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).
To learn more on parabolae: brainly.com/question/21685473
#SPJ1
Let's factor the top and the bottom.
Top factors 4x + 20 = 4(x + 5)
Bottom x^2 + 2x - 15 = (x + 5)(x - 3)
The gcf is the largest value that will go into both the top and the bottom. In our problem the ONLY thing that will go into top and bottom is x + 5 so that is your GCF. (c)
Answer:
No Solution
Step-by-step explanation:
-3x+6=-3x-5
+5 +5
-3x+11=-3x
+3 +3
11=0
No Solution
Answer:
☥ 
- Write the equation of a line in slope - intercept form that has a slope of -2 and passes through the point ( - 1 , 8 ).
☥ 
☪ 
- Slope ( m ) = -2
- Given point = ( - 1 , 8 )
☪ 
- Equation of a line in slope - intercept form ( i.e y = mx + c )
Let the point ( -1 , 8 ) be ( x₁ , y₁ )
☪ 
plug the known values :
↦ 
↦ 
Distribute -2 through the parentheses :
↦ 
Transpose 8 to right hand side and change it's sign
↦ 
↦ 
And we're done !
Hope I helped!
♡ Have a wonderful day / night ツ
~TheAnimeGirl ♪
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