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3 years ago

-2|2.2x-3.3|=-6.6 solve for x

2 answers:

6 0

-2[2.2x-3.3]=-6.6
[2.2x-3.3]=-6.6 /-2
[2.2x-3.3]=3.3
We have two equations:
1)
2.2x-3.3=3.3
2.2x=3.3+3.3
2.2x=6.6
x=6.6/2.2
x=3

2)
2.2x-3.3=-3.3
2.2x=-3.3+3.3
2.2x=0
x=0/2.2
x=0

Answer: we have two solutions: x=0 and x=3.

Anna35 [415]3 years ago

4 0

-2|2.2x - 3.3| = -6.6. From it: |2.2x - 3.3| = 3.3. We have 2 variants: 1) 2.2x - 3.3 = -3.3. Then 2.2x = -3.3 + 3.3, so 2.2x = 0 => x = 0. 2) 2.2x - 3.3 = 3.3. Then 2.2x = 3.3 + 3.3, so 2.2x = 6.6 => x = 3. Answer: 0; 3.

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Answer:

<h2>This equation has no natural roots.</h2>

Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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50 points! I understand A. and B. but I would really appreciate help with C.

FromTheMoon [43]

Answer:

$51.72\text{ cells per hour}$

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

So, we are given that the quadratic curve of the trend is the function:

$P(t)=6.10t^2-9.28t+16.43$

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

$\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]$

Expand:

$P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]$

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

$P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]$

Differentiate. Use the power rule:

$P'(t)=6.10(2t)-9.28(1)$

Simplify:

$P'(t)=12.20t-9.28$

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

$P'(5)=12.20(5)-9.28$

Multiply:

$P'(5)=61-9.28$

Subtract:

$P'(5)=51.72$

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

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