Answer:
10sqrt3+22
Step-by-step explanation:
Ok, let us imagine it as a sort of rectangle split upon its diagonal.
Using that, we can Pythag it out,
11^2+b^2=14^2
121+b^2=196
b^2=75
b=sqrt75
b=5sqrt3
Ok, using this info, we find the perimeter,
5sqrt3+5sqrt3+11+11
10sqrt3+22
The answer is 10sqrt3+22
Answer:
4j + 2
Step-by-step explanation:
Distribute:
(2j * 2) + (1 * 2)
4j + 2
Answer:
1036 students
Step-by-step explanation:
Let the number of students at West High be "w" and the number of students at East High be "e"
West High population is 250 FEWER than TWICE of East High, we can write:
w = 2e - 250
Total students in both schools is 2858, so we can write 2nd equation as:
e + w = 2858
We can replace 1st equation in 2nd to get an equation in e, and find "e":
e + w = 2858
e + (2e - 250) = 2858
3e - 250 = 2858
3e = 2858 + 250
3e = 3108
e = 3108/3
e = 1036
Hence,
number of students attending East High School = 1036 students
Answer:
The person would have to play 2 games for the two bowling alleys to cost the same amount
Step-by-step explanation:
Assume that the number of games that makes the two costs equal is x
∵ A bowling alley charges $2.50 per game plus $4 to rent shoes
∵ The number of games is x
∴ The cost = 2.50x + 4
∵ A second bowling alley charges $4 per game plus $1 to rent shoes
∵ The number of games is x
∴ The cost = 4x + 1
∵ They have the same cost
→ Equate the 2 expressions above
∴ 4x + 1 = 2.50x + 4
→ Subtract 2.50x from both sides
∵ 4x - 2.50x + 1 = 2.50x - 2.50x + 4
∴ 1.50x + 1 = 4
→ Subtract 1 from both sides
∵ 1.50x + 1 - 1 = 4 - 1
∴ 1.50x = 3
→ Divide both sides by 1.50
∴ x = 2
∴ The person would have to play 2 games for the two bowling alleys to
cost the same amount
