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Vera_Pavlovna [14]
3 years ago
13

Q1: Identify the graph of the equation and write an equation of the translated or rotated graph in general form.

Mathematics
1 answer:
marin [14]3 years ago
3 0

Answer:

C. hyperbola; 9x^2-25y^2-250y-850=0

Step-by-step explanation:

The given conic has equation:

9x^2-25y^2=225

Divide through by 225.

\frac{9x^2}{225}-\frac{25y^2}{225}=\frac{225}{225}

\frac{x^2}{25}-\frac{y^2}{9}=1

This is a hyperbola centered at the origin.

The hyperbola has been translated from the origin to (0,5).

The translated hyperbola will have equation;

\frac{(x-0)^2}{25}-\frac{(y-5)^2}{9}=1

Multiply through by 225.

9(x-0)^2-25(y-5)^2=225

Expand

9x^2-25(y^2-10y+25)=225

9x^2-25y^2+250y-625=225

Rewrite in general form;

9x^2-25y^2+250y-625-225=0

9x^2-25y^2+250y-850=0

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Answer:

the second choice is correct

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = \frac{3}{4} x - 9 is in this form

with slope m = \frac{3}{4}

• Parallel lines have equal slopes, hence

y = \frac{3}{4} x + c ← is the partial equation of the parallel line

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- 18 = - 6 + c ⇒ c = - 18 + 6 = - 12

y = \frac{3}{4} x - 12 ← equation of parallel line



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Answer:

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