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Mashcka [7]
3 years ago
5

Is it possible to express every decimal as a fraction (without rounding)?

Mathematics
1 answer:
rusak2 [61]3 years ago
4 0

Yes, with exceptions. It is possible to express every decimal as a fraction,
without rounding, unless the decimal is non-terminating AND non-repeating.

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What property can we apply to isolate the term, 0.25f?
melomori [17]

Answer:subtraction property of equality

Step-by-step explanation:

8 0
3 years ago
Which input value produces the same output value for the two functions ​
Lady bird [3.3K]

Answer:

Completion to the first table for f(x)=\frac{2}{3} x+7 is {-1, 1, 3, 5}

Completion to the second table for g(x)=2x+16\\ is { -8, -2, 4, 10}

the option is x=-6

Step-by-step explanation:

\frac{2}{3} (-12)+7= -1

\frac{2}{3} (-9)+7=1

\frac{2}{3} (-6)+7=3

\frac{2}{3} (-3)+7=5

2(-12)+16=-8

2(-9)+16=-2

2(-6)+16=4

2(-3)+16=10

Hope this helps and is correct.

6 0
3 years ago
The first quartile of a data set is 72, and the third quartile is 92. Which of these values in the data set is an outlier? A.61
marishachu [46]
IQR = Q3 - Q1 = 92 - 72 = 20
20 * 1.5 = 30

72 - 30 = 42....outlier is anything below 42
92 + 30 = 122...outlier is anything above 122

so the outlier is 41
3 0
3 years ago
Of the 2,598,960 different five-card hands possible from a deck of 52 playing cards, how many would contain all black cards.
kumpel [21]

Answer: 65,780

Step-by-step explanation:

When we select r things from n things , we use combinations and the number of ways to select r things = ^nC_r=\dfrac{n!}{(n-r)!r!}

Given : The total number of playing cards in a deck = 52

The number of different five-card hands possible from a deck = 2,598,960

In a deck , there are 26 black cards and 26 red cards.

The number of ways to select 5 cards from 26 cards = ^{26}C_{5}=\dfrac{26!}{(26-5)!5!}

=\dfrac{26\times25\times24\times23\times22\times21!}{21!(120)}=65780

Hence, the number of different five-card hands possible from a deck of 52 playing cards such that all are black cards = 65,780

3 0
4 years ago
a large balloon in the shape of a sphere is being filled with helium. The balloon has a radius of 1 foot. Helium costs $0.80 per
zhenek [66]

Answer:

$3.35

Step-by-step explanation:

volume of balloon in the shape of sphere= 4/3 * pi * r^3 = 4.189 cubic foot

cost of 1 cubic foot of helium = 0.8

cost of 1 * 4.189 cubic foot of helium = 0.8 * 4.189 = 3.35

4 0
3 years ago
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