Jason's scores : 80 90 95 85 70 and
Jill's score : 70 75 90 100 95.
Mean of Jason's scores = 
Mean of Jill's scores = 
Now, in order to find the mean absolute deviation, need to find the difference of each score from means.
<u>Mean absolute deviation for Jason's scores.</u>
|84-80| = 4
|84-90| = 6
|84-95| = 9
|84-85| = 1
|84-70|= 14

<u>Mean absolute deviation for Jill's scores</u>
|86-70| = 16
|86-75| = 11
|86-90| = 4
|86-100| = 14
|86-95|= 9

Jill got average quiz score 86 and Jason got 84.
Therefore, Jill got better quiz average.
Also, the mean absolute deviation for Jason scores is less that is 6.8 than 10.8.
Therefore, Jason got more consistent grades.
Answer:10.25-r= hourly rate
Step-by-step explanation:
i < 3u
Step-by-step explanation:
6i < 5i + 3u
6i - 5i < 3u
i < 3u
Answer:
7 * 4 * 12 = 336sq cm
Step-by-step explanation:
Hoped this helped
Answer:
131.14
Step-by-step explanation:
Hope this helps!! Good luck!!