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boyakko [2]
3 years ago
13

A map of a highway has a scale of 2 inches =45 miles. The length of the highway on the map is 6 inches. There are 11 rest stops

equally spaced on the highway, including one at each end. You are making a new map with a scale of 1 inch = 30 miles. How far apart are the rest stops on the new map?
Mathematics
1 answer:
Elenna [48]3 years ago
4 0

Answer:

each rest stop is 0.45  inches apart on the new map.

Step-by-step explanation:

First, we need to figure out how long is the highway. since 6/2 = 3, we know that the length of the highway is equal to 45*3. 45*3 = 135.

Now since the beginning stop doesn't count(it's at the 0 miles point and normal dividing would not count 0), so we know that there is 10 stops.

Since on the new map there was 30 miles in a inch, 135 miles on the new map would equal to 4.5 inches(135 = 120+15 = 4*30+0.5*30). 4.5/10 = 0.45 inches. So basically the rest stops are 0.45 inches apart.

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1782 cm³

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3 years ago
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3 years ago
What are the fourth roots of 6+6√(3i) ?
Helen [10]

Answer:

Step-by-step explanation:

The genral form of a complex number in rectangular plane is expressed as z = x+iy

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∅ is teh argument = arctan y/x

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r = √36+108

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When n = 1;

z1 =  12^1/4(cosπ/3+isinn/3)

z1 = 12^1/4cis(π/3)

when n = 2;

z2 = 12^1/4(cos2π/3+isin2π/3)

z2 = 12^1/4cis(2π/3)

when n = 3;

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when n = 4;

z2 = 12^1/4(cos4π/3+isin4π/3)

z2 = 12^1/4cis(4π/3)

8 0
3 years ago
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